This is my first time making a Fillomino. Hope you enjoy!

Fillomino (taken from Nikoli):

  • Fill in all empty cells with numbers under the following rules.
  • Divide all of the board into blocks.
  • Fill each block with the same number horizontally or vertically.
  • Each block contains as many cells as the number in the block.
  • Same sized blocks cannot touch each other, horizontally or vertically.

enter image description here

And here is a handy puzz.link for your solving convinience.

(Accepted answer contains complete explanation of answer.)

  • 3
    $\begingroup$ This has multiple solutions. $\endgroup$ – Lukas Rotter Apr 5 at 14:36

To expand Lukas Rotter's comment into an answer,

We can get this far by logical deduction ("escape" to make room for a polyomino, draw walls to prevent two polyominoes of the same type from touching, fill all room left, etc.):

logical end

However, the 6 and 13 can fill the remaining squares near them either way. Also, the empty 3-area on the bottom row can be 1/2/2 or 3/3/3. This has no unique solution. (There are in fact exactly 4 solutions)

  • $\begingroup$ Nooooo, so close to a unique solution! I guess you get a checkmark for explaining why it has multiple solutions, but still, I worked so hard on this, explaining my not-so-activeness lately. Is there like a website that chekcs if your puzzles have multiple solutions or something? And, sorry for the failed puzzle :( $\endgroup$ – Anonymus 25- Reinstate Monica Apr 5 at 15:09
  • 1
    $\begingroup$ Test-solving, especially if you can get another person to test-solve, is the best way to make sure your puzzle 1) has a unique solution and 2) is at the appropriate difficulty level $\endgroup$ – bobble Apr 5 at 15:11
  • 3
    $\begingroup$ @Anonymus25-ReinstateMonica You should solve them with pure logic. Don't make any marks that you are not 100% sure of - only write something down when you are unsure of all other options. (This is the intended method for [grid-deduction] puzzles in general, but it's especially important for uniqueness checking.) $\endgroup$ – Deusovi Apr 5 at 16:58

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