4
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Inspired by encrypted fruits and vegetables, this simple puzzle encrypts a set of things having a common topic. So, please, figure out the topic itself (unlike the linked questions, clues are comma-separated here unless the commas are within parentheses, braces etc.):

  1. 🤘, $\boxed{6}+\alpha\to?$
  2. $\dfrac{F}{x}$, 🌙
  3. $\boxed{83}$, 🏪
  4. $\boxed{19}$, 🇬🇧$(v_4-v_1)$
  5. $0.0075\ \mathrm{mmHg}$, 🪟[0], $\{0,1,2,...\}$
  6. $I^2Rt$, $\boxed{92}$, $\approx7.38906$, $0.10197\ \mathrm{kgf}$
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1 Answer 1

4
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These rebuses resolve as follows:

  1. 🤘, $\boxed{6}+\alpha\to?$

ROOK = ROCK, changing C (element#6 = Carbon) to O by adding 12 alphabet positions (alpha - this element's atomic number - is 12) [NB OP's intent was that Carbon plus an alpha particle becomes Oxygen, i.e. C becomes O]

  1. $\dfrac{F}{x}$, 🌙

KNIGHT = K (F=kx, Hooke's Law) + NIGHT

  1. $\boxed{83}$, 🏪

BISHOP = Bi (element#83 = Bismuth) + SHOP

  1. $\boxed{19}$, 🇬🇧$(v_4-v_1)$

KING = K (element#19 = Potassium) + (possibly) ENG, performing some kind of vowel manipulation I can't quite pinpoint...?

  1. $0.0075\ \mathrm{mmHg}$, 🪟[0], $\{0,1,2,...\}$

PAWN = Pa (Pascal) + W (0th element of WINDOW) + N (the set of natural numbers)

  1. $I^2Rt$, $\boxed{92}$, $\approx7.38906$, $0.10197\ \mathrm{kgf}$

QUEEN = Q (Joule's Law) + U (element#92 = Uranium) + EE (7.38906 is approximately e squared) + N (Newton)

All of these are:

CHESS PIECES!

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4
  • 1
    $\begingroup$ Wow you solved it all before I attached a community wiki $\endgroup$
    – 00xxqhxx00
    Mar 18, 2021 at 8:08
  • $\begingroup$ Great! However, the intended solution for 1 was a bit different, namely rot13(nqqvat nycun cnegvpyr gb pneoba cebqhprf bkltra). Also for 5, rot13(gur rzbwv vf "jvaqbj", naq gnxvat mrebgu ryrzrag [0] bs "jvaqbj" vf "j"). $\endgroup$
    – trolley813
    Mar 18, 2021 at 8:26
  • 1
    $\begingroup$ @trolley813 Aha, okay, that makes more sense! I'll amend my answer, and see if I can nail down 4 completely too... $\endgroup$
    – Stiv
    Mar 18, 2021 at 8:54
  • $\begingroup$ Well, the intended meaning for 4 was rot13(va Ratyvfu tenzzne (urapr gur HX synt), I4 qrfvtangrf cerfrag cnegvpvcyr bs n ireo (r.t. ernqvat), naq I1 vf vasvavgvir (r.t. ernq). Fhogenpgvat I1 sebz I4 (bs gur fnzr ireo) yrnirf "vat" fhssvk (gung'f gehr sbe zbfg ireof)). $\endgroup$
    – trolley813
    Mar 19, 2021 at 19:20

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