Inspired by encrypted fruits and vegetables, this simple puzzle encrypts a set of things having a common topic. So, please, figure out the topic itself (unlike the linked questions, clues are comma-separated here unless the commas are within parentheses, braces etc.):

  1. 🤘, $\boxed{6}+\alpha\to?$
  2. $\dfrac{F}{x}$, 🌙
  3. $\boxed{83}$, 🏪
  4. $\boxed{19}$, 🇬🇧$(v_4-v_1)$
  5. $0.0075\ \mathrm{mmHg}$, 🪟[0], $\{0,1,2,...\}$
  6. $I^2Rt$, $\boxed{92}$, $\approx7.38906$, $0.10197\ \mathrm{kgf}$

1 Answer 1


These rebuses resolve as follows:

  1. 🤘, $\boxed{6}+\alpha\to?$

ROOK = ROCK, changing C (element#6 = Carbon) to O by adding 12 alphabet positions (alpha - this element's atomic number - is 12) [NB OP's intent was that Carbon plus an alpha particle becomes Oxygen, i.e. C becomes O]

  1. $\dfrac{F}{x}$, 🌙

KNIGHT = K (F=kx, Hooke's Law) + NIGHT

  1. $\boxed{83}$, 🏪

BISHOP = Bi (element#83 = Bismuth) + SHOP

  1. $\boxed{19}$, 🇬🇧$(v_4-v_1)$

KING = K (element#19 = Potassium) + (possibly) ENG, performing some kind of vowel manipulation I can't quite pinpoint...?

  1. $0.0075\ \mathrm{mmHg}$, 🪟[0], $\{0,1,2,...\}$

PAWN = Pa (Pascal) + W (0th element of WINDOW) + N (the set of natural numbers)

  1. $I^2Rt$, $\boxed{92}$, $\approx7.38906$, $0.10197\ \mathrm{kgf}$

QUEEN = Q (Joule's Law) + U (element#92 = Uranium) + EE (7.38906 is approximately e squared) + N (Newton)

All of these are:


  • 1
    $\begingroup$ Wow you solved it all before I attached a community wiki $\endgroup$
    – 00xxqhxx00
    Mar 18, 2021 at 8:08
  • $\begingroup$ Great! However, the intended solution for 1 was a bit different, namely rot13(nqqvat nycun cnegvpyr gb pneoba cebqhprf bkltra). Also for 5, rot13(gur rzbwv vf "jvaqbj", naq gnxvat mrebgu ryrzrag [0] bs "jvaqbj" vf "j"). $\endgroup$
    – trolley813
    Mar 18, 2021 at 8:26
  • 1
    $\begingroup$ @trolley813 Aha, okay, that makes more sense! I'll amend my answer, and see if I can nail down 4 completely too... $\endgroup$
    – Stiv
    Mar 18, 2021 at 8:54
  • $\begingroup$ Well, the intended meaning for 4 was rot13(va Ratyvfu tenzzne (urapr gur HX synt), I4 qrfvtangrf cerfrag cnegvpvcyr bs n ireo (r.t. ernqvat), naq I1 vf vasvavgvir (r.t. ernq). Fhogenpgvat I1 sebz I4 (bs gur fnzr ireo) yrnirf "vat" fhssvk (gung'f gehr sbe zbfg ireof)). $\endgroup$
    – trolley813
    Mar 19, 2021 at 19:20

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.