I need some help with this 15x15 nonogram

I have been working on this nonogram for some time and can't seen to figure out what to do next...

• how come there are 2 pictures? Feb 26 '21 at 19:03

Look at the seventh column:

With the X at the top of the column, you can completely fill out the rest of the column.

Row, 5 column 15 must be an X, which then yields additional deductions for column 15.

Here's a couple of different places you can go from there, I'll leave the rest for you to solve:

Red squares are black, and grey squares are crosses, using colours to highlight.

Quick explanation:

The top most red must be filled in, regardless whether the other black to the right is part of the 1 or the 3. This greys out the square below, and means the red 3 can be placed as it cannot fit to the right. Furthermore, the bottom grey on the right cannot be filled, as that would make a 4, and from that some of the 6 can be placed.

Good luck! If you need a bit more I can add some

1. In the fifth row,

the rightmost $$3$$ can't start from the right-hand edge, because then it would become $$4$$ with the black cell you've already filled. So the rightmost cell in this row is empty (cross).

Then in the rightmost column,

there's not enough space for the $$6$$ above the fifth row, so all those cells are empty. Now there's ten unknown cells to contain that $$6$$, so the middle two of them at least must be black. That enables you to cross off the rightmost $$1$$ in two rows.

2. In the fourth row,

if the lone black cell in the middle is the $$1$$, then there must be $$3$$ to the left of it with an empty cell in between. Then, reading down from the columns, the three cells below that $$3$$ must be empty, but then the fifth row won't have enough space for its $$3,1,3$$. Contradiction, so the fourth row can be completely filled in up to the middle (two empty cells then two black cells).