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So this challenge is you have (don't have to) make the numbers 1 - 100 by using the numbers 1, 3, 4, 6 only once. I'm stuck on how to make 54. Can anyone help me?

P. S. You can use +, -, รท, x, ! And others you can think of.

Thanks for helping me! I was really stuck on 100.

STOP SAYING THAT I FOUND THIS SOMEWHERE I MADE IT.

Also you can combine numbers like 1 & 3 to 13 or 31

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    $\begingroup$ Welcome to Puzzling! 1) This looks like a puzzle you found elsewhere, and for such puzzles we require attribution. A link, for example. 2) I've removed your request to make a Google Doc because that's not how this site works. Answers go in answers where they can be seen by all, not just the asker. $\endgroup$ – bobble Jan 19 at 22:54
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    $\begingroup$ Number formation puzzles must have the allowed operations very well defined. Otherwise people will come up with floor, ceiling, square root, nth root, nPk, nCk, gamma, zeta, etc. and it quickly goes out of hand. $\endgroup$ – Bubbler Jan 19 at 23:30
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    $\begingroup$ Please stop changing the question you're asking. So far you've asked us to make 51, 54, and 100, all at different times. Either ask for all the numbers or a specific sub-set, then don't change. $\endgroup$ – bobble Jan 20 at 22:00
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    $\begingroup$ Though the site shows only one close reason (which is resolved now I assume), I don't think you addressed my comment above. The allowed operations should be in the form of "this, this, and this are allowed, and you cannot use anything else". $\endgroup$ – Bubbler Jan 21 at 0:47
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How about:

$(6+4)^{(3-1)} = 10^2 = 100 $

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    $\begingroup$ Exponentiation isn't explicitly listed as an allowed operation, but I guess it would fall under "And others you can think of." $\endgroup$ – bobble Jan 19 at 23:05
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With the comment "And others you can think of."

(4+3)!! - 6+1 = 105 - 5 = 100

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