The puzzle is as follows:
A classroom in kindergarten has 35 children. Each of them carry a flag of one, two or three colors. The number of only two-colored flags is double that of the monochrome ones, and the number of flags that have red color is equal to the number of flags that have blue color and equal to the number of flags that have the green color. If eight children have a tricolored flag and two children have a yellow flag only, how many children carry flags of only two colors?
The alternatives given in my book are as follows:
- 19 children
- 18 children
- 15 children
- 16 children
For reference, this problem comes from my Reason and logic book from 2000s. It seems to be an adaptation from a reprinted copy of Martin Gardner's Puzzle carnival from 1970s.
I am confused on how to approach this without much fuss.
I'm not very savvy with these kinds of puzzles, but I could spot here that there are four colors mentioned. Those are: red, green, blue and yellow.
Since it is mentioned that two children carry only a yellow flag. The answer is to find how many flags there are.
But the thing is that the problem mentions bicolored, tricolored and monochrome flags. This makes it confusing.
Can someone help me solve this puzzle relying on Venn-Euler diagrams? I'm not sure how to do this. Since it mentions three sets I believe.
I don't know if a better way to do this exists. But I believe this is the form which would let me better understand.
Can someone help me here please? Because I'm lost.