# Male and Female functions

You are given two goniometric functions:

• Male: $g(\rho, \Theta) = \rho \, \cos\Theta \sin\Theta$
• Female: $f(\rho, \Theta) = \rho \, \cos^2\Theta$

Why are these two functions labeled "male" and "female"?

• Now explain me why the female's value at 90° is 0... – leoll2 Mar 22 '15 at 14:25
• @leoll2 that's a good point ahaha, it should actually be cos²(π-Θ) – Marco Bonelli Mar 22 '15 at 14:33