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This is a chart filled with numbers. The numbers are linked to each other.

30 1 0 29 9 π‘Ž1 6 6
4 77 1 π‘Ž2 2 54 π‘Ž3 2
60 π‘Ž4 9 9 π‘Ž5 1 π‘Ž6 2
6 98 97 π‘Ž7 0 0 43 3
77 8 π‘Ž8 1 π‘Ž9 0 3 8
8 45 0 π‘Ž10 0 40 0 1

The question is: find the value of

π‘Ž1π‘Ž2π‘Ž3...π‘Ž10

Hint 1:

2, 3, 4, 5, 6

Hint 2:

The numbers are related in rows

Hint 3:

The numbers can be chained together

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π‘Ž1π‘Ž2π‘Ž3...π‘Ž10 is:

0 coming from the values 95,21,7,205,9,13,0,15,25,98 (or 952172059130152598 if concatenation, or 0 if multiplication)

Because

As the title and hints allude to, each row reads out 'n' for the equation 10^n=[row # + 1], if one adds a decimal to the front.
Reducing this (solving for n), each row is a list of the digits for log(row # + 1).
For example, for row # 1: log(1+1) = log(2) = .301029995664, so the missing value for π‘Ž1 is 95. For row # 2, log(2+1) = log(3) = .47712125472, and so forth.

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  • 1
    $\begingroup$ Updated concatenation to multiplication $\endgroup$ – Amoz Jan 13 at 15:51

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