A blind prisoner is offered a deal by a king. 3 monks will be sent to his cell over a period of three days,only one monk will be sent to the prisoner's cell on any day. The king may decide to send one monk thrice or all monks might get to visit the prison once or any other combination. 2 out of the three monks always lie, they lie in such a way that whatever they say, there is no possible way for the truth to be interpreted by the listener . The remaining monk always conveys the exact Truth. The prisoner is allowed to ask only one question to each monk per day and the monks are strictly ordered to answer only with a "yes" or a "no" or and if there is no way for the liars to lie and the truth speaker to convey the exact truth by speaking, they leave the room and the prisoner knows about this mannerism of theirs.
At the end of three days, the prisoner is presented before the king and if he is able to point out the nature of the monk who visited him each day and the exact day on which the monk visited him. If he is successful he is set free and if he is not he is sentenced to death. A liar meets him on the first day.
Suggest a possible way in which the prisoner can guarantee his freedom.
Notes: 1)The prisoner does not need to exactly identify the monk who visited him on a particular day. He is blind and it is impossible.
2)For instance, if one liar met the prisoner on the first and second day and the second liar met him on the third,the prisoner's answer to the king should be "a liar met me on the first day, he met me again on the second day and a different liar met me on the third". In this case he will be set free as he has pointed the exact nature (truth speaker/liar)of the monks who have met him and also the exact days on which the monks have met him.