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In the Mensa IQ Check app, the same kind of puzzles keeps coming back. I don't know how to solve it. Can anyone help me?

enter image description here

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Answer

X

Because

The pattern needs the X to repeat

There is a pattern of 5 possible symbols: X # O @ !.

The pattern repeats in a spiral pattern around the square (Starting at the left top corner).

enter image description here

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  • $\begingroup$ What does "the pattern needs the X to repeat" mean? What does the picture show? Please explain more. $\endgroup$ – bobble Oct 22 at 17:46
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    $\begingroup$ @bobble, edited for clarity. $\endgroup$ – MacGyver88 Oct 22 at 17:51
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    $\begingroup$ I see it now, thanks! $\endgroup$ – Jan Oct 22 at 18:17
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    $\begingroup$ Took me about 25 seconds. +1 $\endgroup$ – Tim Oct 24 at 8:32
  • $\begingroup$ @Tim, that's pretty quick. It took me a bit longer than that. lol. $\endgroup$ – MacGyver88 Oct 26 at 15:04
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O

Because

When you draw the bottom-left top-right extended diagonals, there are duplicate symbols sitting next to each other on every line

Bottom-left top-right diagonal

(I think MacGyver88's solution is simpler, so it is probably what the author thought about).

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From the six columns only the fourth contains the same symbol 3 times, namely the symbol $O$. In addition to that, none of the rows contains the same symbol 3 times. If we replace the question mark which is on fourth row with the symbol $X$ then on the fourth row the symbol $X$ appears 3 times as well.

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Or....

Each row has exactly one symbol duplicated. In the ? row the X is already duplicated, meaning the answer must be #, to have all 5 symbols.

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    $\begingroup$ This fails in the third row, where both O and @ are duplicated, or the 5th with ! and # $\endgroup$ – TCooper Oct 23 at 18:55
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Answer

It could be @

Because

The outer two columns have patterns that are copies of each other, with symbols changed. The same is true for the inner 2 columns. If we use @ instead of ? this pattern would be true for column 2 and 5 as well.

But

I think the solution from @MacGyver88 is nicer than this solution, although any of them could be valid.

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  • $\begingroup$ Copies with symbols changed? That makes them non-copies. $\endgroup$ – Tim Oct 24 at 8:33
  • $\begingroup$ @Tim you're right. I've edited the answer. $\endgroup$ – Polygorial Oct 24 at 8:46

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