7
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I made a big mistake with my last post, and the puzzle I presented did not have a unique solution...many thanks to Deusovi for pointing it out, and many apologies to Deusovi and any others who spent time on a failed effort. However, I have been able to fix it, and I believe the puzzle below is uniquely solvable...it does have a fair bit of overlap with the previous attempt.


In this puzzle, there is a single 12x12 grid which contains clues for both a Tapa and a Nurikabe puzzle, to be solved in separate grids. It is up to you to determine which clues go with which puzzle. No clues overlap...a clue is used either for the Nurikabe or the Tapa, and it provides no information for the other, so a Nurikabe clue can be shaded or unshaded in the Tapa, and vice versa. I hope you enjoy! And I hope I didn't mess up again :-)

Grid

Text Version

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| 3 | 1 |   |   |   | 3 |   |   |   |   |   |   |
-------------------------------------------------
|   |   |   |1 4|   |   | 1 |   |   |   |   |1 1|
-------------------------------------------------
|   |2 4|   |   | 3 |   |   |   |   |1 5|   |   |
-------------------------------------------------
|   |   |   |   | 2 | 3 |122|   | 5 |   |   | 2 |
-------------------------------------------------
|   |2 4|   |   |   |1 4|   |   |   |1 4|   | 3 |
-------------------------------------------------
|1 3|   |   |   |   | 4 |   |   |112|   |   | 3 |
-------------------------------------------------
|   |   |   |   | 6 |   | 2 |   |   |   |   | 2 |
-------------------------------------------------
| 7 | 5 |   |   |   | 6 |   |   |113| 4 |   |   |
-------------------------------------------------
|   | 4 |112|   |   |1 5|   |   |   |   |2 4|   |
-------------------------------------------------
|1 2|   |   |   |   |   |   |   |   |   |   |   |
-------------------------------------------------
|   |   |   |   |   | 4 |3 3|   |   |   |   | 3 |
-------------------------------------------------
|   | 1 | 2 | 2 |   |   |   |   |1 1| 2 | 3 |   |
-------------------------------------------------
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5
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First, we assign multi-digit clues to the Tapa:

enter image description here

And more clue assignments:

The 7 on the left cannot be part of the Tapa. The 5 then must be, and the 4 must not be.

enter image description here

Now we can do some more advanced logic on both grids:

The 5 near the upper right is the only thing that can access the top-right 2x2.
To access the [12] clue near the bottom, the 1 in the bottom left cannot be part of the Tapa.
We can also do some logic with the 2 in the upper middle, which must be part of the Tapa. Once the 1 is assigned to the Nurikabe, that pins down the 5's location.
enter image description here

And some more logic in the center:

After a bit more Nurikabe logic, we can assign the lower 6 to Nurikabe because it can't be satisfied in the Tapa. The 2 is broken by the [15] clue in the Tapa, so it must be in the Nurikabe.
enter image description here

Some miscellaneous logic in various places:

Only the unassigned 4 clue can reach that newly-created hole on the right of the Nurikabe.
(I also noticed that more of the [15] near the top right of the Tapa could be determined, based on the nearby 11.)
enter image description here

Some connectivity logic:

The top-left section of the Tapa must escape rightwards, making the 3 a part of the Nurikabe. We can also do some connectivity logic on the two nearby [24] clues.
enter image description here

Now, there's a tricky connectivity step:

enter image description here
How can the top section connect to the bottom? Assuming it's not using the [121] clue, we run into a problem: we'll have to invalidate two adjacent clues in the Tapa (either by shading over them or by shading too many cells around them). And so that would assign two adjacent clues to the Nurikabe, causing a contradiction.

With this, we can fill out most of the Tapa! enter image description here

Turning to the Nurikabe once again:

There's some tricky logic in the bottom right.
enter image description here
First, the leftmost blue cell here is in accessible, and so the right one must be caught by one of the two 3s. The white cell that's above-left of the shaded blue can only be reached by the 6, and that would cut off the shaded cells above it. So the 6 is forced along the orange path.
enter image description here And now, look at the area I've marked in blue. The only thing that can stop that from being a 2x2 shaded area is the 2 clue inside it (because a 3 must take the top cell, and we can't use both 3s without the bottom right corner being disconnected).

And now we've assigned all the clues, and can finish off both of the puzzles!

enter image description here

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1
  • $\begingroup$ That's it! Awesome job...thank you so much for coming back to claim it. Hope you enjoyed! $\endgroup$ – Jeremy Dover Oct 3 '20 at 16:27

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