A wealthy famer has a large estate in the shape of an irregular squarish octogon. In the middle he has a rectangular retention basin for storing water.

He is getting old and discusses with his wife about passing the land to his children.

- I want to split the land in four identical parts, one for each of our sons. This way there is no jealousy between them and they will live in peace and harmony. I can divide it easily here along the north-south axis and there along the east-west axis. The basin will remains untouched.
- Four parts? You are a bigot! And this is the 21st century. What about your two daughters? They worked just as hard as the boys to make this farm what it is. You cannot just ignore them!
- But they will marry and move away.
- And maybe they will marry and stay.
- But It has always been like this in my family. The land goes to the sons.
- Exactly, and this has to stop! Times change.
- OK, I agree with you (actually he didn't). But how can I share the land equally? I need all lots to have the same size and same shape. It is not possible! What can I do? If you come up with a way to split this land in six identical lots, then OK, the girls will get their share. If not, just let me proceed according to my plan and to my "20th century" traditions.

The farmer is confident he won this argument. The first time in years. But the wife is smarter than he thinks and she is determined to see her daughters treated equally.

What did the wife come up with?


octoconal field with a hole in the middle

Forget about cutting the land in four. That was just the teaser. Cut the land in six identical lots having the same size and the same shape, possibly mirrored.

The lots must be connex, i.e. in one piece. Access to the water is not required. (It is just a justification for the hole.)

The picture is accurate. All edges are horizontal, vertical or at 45 degrees. The rectangle is prefectly centered. That should be enough to solve it.
But if you need to know, the rectangle has size ($1+\sqrt{2}$) by $1$, the octogon/octagon sides have lengths $2 / (\sqrt{2}-1)$ and $\sqrt{2}$ alternated.

  • $\begingroup$ What are the dimensions of the plot? Are we just supposed to guess? $\endgroup$
    – Deusovi
    Commented Aug 18, 2020 at 23:02
  • 1
    $\begingroup$ octogon n. (plural octogons) Obsolete form of octagon. $\endgroup$
    – Florian F
    Commented Aug 18, 2020 at 23:02
  • $\begingroup$ Despite being "irregular" it is in fact symmetric, right? And the rectangle and octagon share a centre? $\endgroup$ Commented Aug 18, 2020 at 23:07
  • $\begingroup$ Does "identical" mean "mirror images are forbidden"? $\endgroup$
    – Bass
    Commented Aug 18, 2020 at 23:08
  • $\begingroup$ As the farmer's initial plan implies, mirroring is acceptable. $\endgroup$
    – Florian F
    Commented Aug 18, 2020 at 23:12

1 Answer 1



enter image description here This solution has not one but two concave angles.



Random observations:

enter image description here Most of the tile's boundary touches the boundary of the large shape. Only the bits marked in red don't ever. This together with the mix of rotational and mirror symmetries (and connectedness) rules out any obvious "harmless" modifications. The solution may therefore be unique. No proof, though.

  • 1
    $\begingroup$ @athin Otherwise it would have been obvious to you I take it? ;-P $\endgroup$ Commented Aug 20, 2020 at 8:07
  • 1
    $\begingroup$ and here I was thinking "connex" was another typo... $\endgroup$
    – oAlt
    Commented Aug 20, 2020 at 9:33
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    $\begingroup$ I even said "connex, i.e. in one piece". Anyway... We obviously have a winner. Congratulations! $\endgroup$
    – Florian F
    Commented Aug 20, 2020 at 13:54
  • 1
    $\begingroup$ @FlorianF The moment the pieces fell into place was quite satisfying, so thanks for this beautiful if devilishly hard puzzle. And see you in court for wilfully wasting lots and lots of our working hours ;-) $\endgroup$ Commented Aug 20, 2020 at 14:09
  • 2
    $\begingroup$ You could have saved your time by just asking the farmer's wife. $\endgroup$
    – Florian F
    Commented Aug 20, 2020 at 17:15

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