# Arrange ten pawns into ten lines of three

This is not a chess problem!

In the following position you can see six pawns that have been arranged into lines of three. Each pawn stands at the intersection of exactly two lines and each line contains exactly three pawns.

For this problem 2 pawns don't count as a line.

Can you arrange ten pawns in such a way that each pawn is at the intersection of exactly three lines and each line contains exactly 3 pawns?

Each pawn must be positioned in the exact center of a square of a standard 8x8 chessboard.

• The pawns should be in the center of a tile in a standard chessboard, right? Commented Jul 18, 2020 at 17:24
• Oops! Indeed. Corrected. I wanted to check if you people pay attention. :-) Commented Jul 18, 2020 at 21:36
• a line could also be drawn through the f7 and h3 pawns, only touching those two, but I think you meant that lines with < 3 pawns can be ignored. Commented Jul 19, 2020 at 8:01
• Yes. I am interested in alignments and 2 pawns don't count as an alignment. I updated the question. Commented Jul 19, 2020 at 11:03
• never mind, something was wrong with my vision I guess. Commented Aug 1, 2020 at 0:07