This is not a chess problem!
In the following position you can see six pawns that have been arranged into lines of three. Each pawn stands at the intersection of exactly two lines and each line contains exactly three pawns.
For this problem 2 pawns don't count as a line.
Can you arrange ten pawns in such a way that each pawn is at the intersection of exactly three lines and each line contains exactly 3 pawns?
Each pawn must be positioned in the exact center of a square of a standard 8x8 chessboard.