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I have a riddle, you might wanna help solve.

Just imagine, we would like to change the sequence (that works very well now [in German there is the term "funktioniert 1A" - which translates into somewhat like "works optimally" and which could be a clue]) of the following numbers. What could that sequence be?

84474, 349272, 1284192, 6648480, 24948000, 63504000, 97511040, 240166080

Additionally, one number is missing! Please tell me which one and include it into the sequence I'm searching for!

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The solution is:

84474, 240166080, 6648480, 1284192, 63504000, 349272, 5027400, 97511040, 24948000

Explanation:

Step 1: Perform integer factorization for each number
Step 2: Convert each integer to a letter 1A (1=A)
Step 3: Each number corresponds to a "starter" Pokémon
Step 4: Find the missing one, convert to number
Step 5: Sort alphabetically

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    $\begingroup$ Why is this the solution? Please edit your answer to explain. $\endgroup$
    – Rand al'Thor
    Commented May 5, 2020 at 8:24
  • $\begingroup$ Could you demonstrate your Step 3 with an example breakdown please? I'm struggling to follow your process and am probably not the only one. Thanks :) $\endgroup$
    – Stiv
    Commented May 5, 2020 at 23:29
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Partial answer:

The second series fits the function

g(x) = (29*x^7 - 694*x^6 + 6560*x^5 - 31150*x^4 + 77711*x^3 - 94876*x^2 + 46740*x + 46080)/720

When you insert the values 0 - 7 for x, then the values of the series are emitted in ascending order, but you write, that the order may be other than given. When inserting the value 8, then the result is 546, which might be the result that you are looking for!

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