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"I will, of course, kill you if you don't answer. But that's a given, isn't it?" The Enemy says. "So come, Zero, and show me your legendary brain."

$2.828,\quad5.196,\quad11.180,\quad18.520,\quad x$

What is $x$?

C2L, Part 1.

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  • $\begingroup$ What is "C2L, Part 1" ? $\endgroup$
    – Rubio
    Mar 5, 2018 at 17:31
  • $\begingroup$ @Rubio Part 1 of a series of puzzles I'm going to give. $\endgroup$
    – Buddha
    Mar 5, 2018 at 17:39
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    $\begingroup$ @Buddha you should probably cite your source, which seems to also be the TORN forums: torn.com/… $\endgroup$
    – Quintec
    Mar 5, 2018 at 18:56
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    $\begingroup$ This question does not appear to be about creation and solving of puzzles, within the scope defined in the help center. $\endgroup$ Mar 7, 2018 at 16:25

1 Answer 1

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The answer is

$36.482$ or $36.483$ depending on whether the numbers are truncated or rounded at 3 decimals.

Explanation:

The numbers are $2 \sqrt{2}$, $3 \sqrt{3}$, $5 \sqrt{5}$, $7 \sqrt{7}$ where $2$, $3$, $5$, $7$ are successive primes. The next prime is $11$ to give $11 \sqrt{11}=36.4828726...$.

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    $\begingroup$ How do you find this answer? I mean I have no idea how a person can think like this? $\endgroup$ Mar 6, 2018 at 3:58
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    $\begingroup$ @IamtheMostStupidPerson I guess it's because it has to follow some fixed rule that you can try out. Also, prime numbers are always popular. So you could try different combinations of prime numbers, once you found out how the first number came to be. Another possibility is, that you actually know what $2.828$ is because you have used it at school, at work etc. and start working your way up from there. For instance, I work as a developer and $\sqrt{2}=1.414$ appears quite often in my tasks, so it's useful to remember the decimal value. Then you can immediately see the connection to $2.828$. $\endgroup$
    – QBrute
    Mar 6, 2018 at 6:38
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    $\begingroup$ Yes, for me $2.828$ was a dead give-away. On a hunch I then divided the next number by $3$, recognised the result, and the rest followed. $\endgroup$ Mar 6, 2018 at 7:29

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