This is a variant on a well-known logic puzzle. It is not intended to be difficult, given that we are now officially in the “silly season”. Yesterday I won first prize in a Chess tournament, only to discover someone forgot to put a cheque in my envelope. Today, I saw a driver who forgot to display his D-plates when driving home (D stands for a word that rhymes with “Thick Ed” and cannot be represented using Alphabetic String Theory for several reasons).
But I digress …
Standard Spider Solitaire rules apply. It is relatively straightforward to expose all the cards in the tableau without dealing the remaining 10 cards in the stock.
Consider the following statements
Every hidden card that is directly underneath a Three of any suit (*) is a King
Every hidden card that is directly underneath a Heart of any rank (*) is a King
Every hidden card that is directly underneath a Three of any suit (*) is a Club
Every hidden card that is directly underneath an Eight of any suit (*) is a Three
(*) Can be either exposed or hidden.
QUESTION: For each of the four statements above, what is the minimum number of face-down cards we must expose before we are certain to verify the correctness/falsehood of said statement?
For purposes of answering the question, assume that you cannot deal the remaining ten cards in the stock.
You must answer correctly for all four statements above to earn the checkmark. There will be no partial credit or feedback other than “at least one of your answers is wrong” 😊