This is my toughest invention so far, not sure if it's already been done but here it goes.
Move a single stick to obtain a correct equality. (To be clear: the stick needs to be moved and placed down to be part of the new figure; not 'removed').
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$\begingroup$ Must all numbers be represented as proper Roman or Arabic numerals? $\endgroup$– SeanCommented Feb 10, 2022 at 17:20
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$\begingroup$ I'd never seen this before, very clever $\endgroup$– qdreadCommented Feb 10, 2022 at 20:34
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$\begingroup$ I want to answer, but does a rot13(vardhnyvgl) count? $\endgroup$– NautilusCommented Feb 14, 2022 at 10:49
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3 Answers
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I believe what you're looking for is this:
where
$e^{-i\pi}=3-4=-1$
The title alludes to
the complex number $i$ found in the solution.
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$\begingroup$ Inconsistent that a match is
iin one case and1in another $\endgroup$ Commented Feb 11, 2022 at 15:21 -
1$\begingroup$ not to be that guy, but technically, no match represents the number 1. the roman numerals are iii and iv. I will grant you that they're still interpreted differently haha $\endgroup$– juiciferCommented Feb 11, 2022 at 16:35
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1$\begingroup$ @juicifer to be fair they're all interpreted as
i$\endgroup$– somebodyCommented Feb 11, 2022 at 19:43 -
$\begingroup$ true, but they certainly don't mean the same thing $\endgroup$– juiciferCommented Feb 11, 2022 at 20:19
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$\begingroup$ @somebody Or rather all interpreted as
I(capitalizedi). $\endgroup$– WhatsUpCommented Feb 12, 2022 at 3:42
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My answer:
$-8^{-iii} = ii-iv$
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3$\begingroup$ I was really hoping that would be right too but -8^(1/3) = -2, not -8^-3. $\endgroup$– qdreadCommented Feb 10, 2022 at 19:58
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$\begingroup$ I always intended to start with a bang. How embarrassing for me to have for gotten. $\endgroup$ Commented Feb 10, 2022 at 20:09
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Assuming you have bad stick "handwriting"
This gives you
8-3 = 3 + 2
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1$\begingroup$ I'm finding it difficult to interpret the "-III" as "minus three" instead of "to the negative three" due to its placement in an exponent position $\endgroup$– bobbleCommented Feb 10, 2022 at 23:36
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1$\begingroup$ It's a bit of a stretch, but that was what I was referring to with the bad handwriting comment $\endgroup$– TravisCommented Feb 10, 2022 at 23:41