Timeline for Find the unique passcode
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 19, 2020 at 14:01 | comment | added | user40528 | As fast as ever! Well done :) You can, by looking at the other end of the number, speed things up a bit more too: properties of squares quickly constrain the square-root to be of the form $1uv2$ or $1uv8$ and then considering the square of that you find that either $4v = z$ or $16v+6=z$. But this is an easy-to-follow way of doing it, and I like it! | |
| Jun 19, 2020 at 14:00 | comment | added | Gareth McCaughan♦ | (I have the feeling it might be possible to reduce the amount of brute force a bit.) | |
| Jun 19, 2020 at 13:58 | vote | accept | CommunityBot | ||
| Jun 19, 2020 at 13:56 | history | answered | Gareth McCaughan♦ | CC BY-SA 4.0 |