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Added text from the rules.
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Lanny Strack
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I don't know why you have concluded that the scoring ambiguity is not resolved by the Wikipedia page. There is text on that page which, to me, clearly addresses and resolves this issue:

If there are duplicate colours in the guess, they cannot all be awarded a key peg unless they correspond to the same number of duplicate colours in the hidden code. For example, if the hidden code is white-white-black-black and the player guesses white-white-white-black, the codemaker will award two colored key pegs for the two correct whites, nothing for the third white as there is not a third white in the code, and a colored key peg for the black. No indication is given of the fact that the code also includes a second black.

This text supports your option 2.

Furthermore, the original game box bottom also specifies rules, and those rules clearly address this question as well, also in support of your option 2. The image of the game box is here: https://i.sstatic.net/N1XDS.jpg. The relevant text is here:

ForA White Key Peg is placed ... for each hidden Code Peg which is matched in colour but not position by a peg placed by the Codebreaker. For example, one white Key Peg is placed if one red Code Peg is hidden, and the Codebreaker has placed two or more red Code Pegs in the wrong position.

I don't know why you have concluded that the scoring ambiguity is not resolved by the Wikipedia page. There is text on that page which, to me, clearly addresses and resolves this issue:

If there are duplicate colours in the guess, they cannot all be awarded a key peg unless they correspond to the same number of duplicate colours in the hidden code. For example, if the hidden code is white-white-black-black and the player guesses white-white-white-black, the codemaker will award two colored key pegs for the two correct whites, nothing for the third white as there is not a third white in the code, and a colored key peg for the black. No indication is given of the fact that the code also includes a second black.

This text supports your option 2.

Furthermore, the original game box bottom also specifies rules, and those rules clearly address this question as well, also in support of your option 2. The image of the game box is here: https://i.sstatic.net/N1XDS.jpg. The relevant text is here:

For example, one white Key Peg is placed if one red Code Peg is hidden, and the Codebreaker has placed two or more red Code Pegs in the wrong position.

I don't know why you have concluded that the scoring ambiguity is not resolved by the Wikipedia page. There is text on that page which, to me, clearly addresses and resolves this issue:

If there are duplicate colours in the guess, they cannot all be awarded a key peg unless they correspond to the same number of duplicate colours in the hidden code. For example, if the hidden code is white-white-black-black and the player guesses white-white-white-black, the codemaker will award two colored key pegs for the two correct whites, nothing for the third white as there is not a third white in the code, and a colored key peg for the black. No indication is given of the fact that the code also includes a second black.

This text supports your option 2.

Furthermore, the original game box bottom also specifies rules, and those rules clearly address this question as well, also in support of your option 2. The image of the game box is here: https://i.sstatic.net/N1XDS.jpg. The relevant text is here:

A White Key Peg is placed ... for each hidden Code Peg which is matched in colour but not position by a peg placed by the Codebreaker. For example, one white Key Peg is placed if one red Code Peg is hidden, and the Codebreaker has placed two or more red Code Pegs in the wrong position.

Source Link
Lanny Strack
  • 6.1k
  • 1
  • 15
  • 27

I don't know why you have concluded that the scoring ambiguity is not resolved by the Wikipedia page. There is text on that page which, to me, clearly addresses and resolves this issue:

If there are duplicate colours in the guess, they cannot all be awarded a key peg unless they correspond to the same number of duplicate colours in the hidden code. For example, if the hidden code is white-white-black-black and the player guesses white-white-white-black, the codemaker will award two colored key pegs for the two correct whites, nothing for the third white as there is not a third white in the code, and a colored key peg for the black. No indication is given of the fact that the code also includes a second black.

This text supports your option 2.

Furthermore, the original game box bottom also specifies rules, and those rules clearly address this question as well, also in support of your option 2. The image of the game box is here: https://i.sstatic.net/N1XDS.jpg. The relevant text is here:

For example, one white Key Peg is placed if one red Code Peg is hidden, and the Codebreaker has placed two or more red Code Pegs in the wrong position.