Timeline for How many ways are there to read 5556789 without repeating digits?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Nov 16, 2020 at 22:02 | comment | added | Chris Steinbeck Bell | @Neil Therefore the sum symbol you had just used would make much more sense as 3 ways plus 2 ways hence 5 ways in total. This would also apply for the number 2 which it could be 1 to indicate another way, hence $1+1+3=5$ ways. | |
| Nov 16, 2020 at 21:50 | comment | added | Chris Steinbeck Bell | @Neil Thanks! But I'd like to say that the numbers in the first row of your picture are a bit misleading. When I'm reading $1$ and $2$ and $5$ what are those?. Are these the total number or the individual number of ways?. I'm understanding that each route in the arrows account for one way. I must say that the missing route which I haven't noticed is that you can go in the five from the middle up and then down. I think the third picture from the right in the first row instead of having 5 should have had 3 to indicate the total number of ways indicated by the arrows. | |
| Nov 11, 2020 at 9:59 | comment | added | Neil | @ChrisSteinbeckBell edited my answer with a picture, but the generalization to calculate the number in an automatic way without bruteforcing with a program is beyond my graph knowledge. | |
| Nov 11, 2020 at 9:56 | history | edited | Neil | CC BY-SA 4.0 |
added 474 characters in body
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| Nov 9, 2020 at 3:57 | comment | added | Chris Steinbeck Bell | @Neil Howdy! It's been like a year after this answer has been posted and I'm still not getting the idea. How did you got to those five ways for the five in the leftmost part in the second row?. Can you explain in more details how did you got to them?. I'm still struggling with that part. I've already counted the ways for that number but I'm getting four different ways not five, how did you do that account for also the five in the middle?. | |
| Dec 21, 2019 at 3:24 | comment | added | Chris Steinbeck Bell | @GentlePurpleRain It was referring to Neil's answer. But again I'm not getting the idea of adding the extra $5$. I mean, I understand that to get the number I have to return a step behind, but if I do that I end up getting four times digit $5$ and not three as requested. | |
| Dec 21, 2019 at 3:20 | comment | added | GentlePurpleRain | @Chris I'm not sure if you meant this for me, since you put it on Neil's answer, not mine... | |
| Dec 21, 2019 at 3:08 | comment | added | Chris Steinbeck Bell | @GentlePurpleRain I'm trying very hard to understand what you mean by your explanation. Perhaps can you add a diagram so I could understand better?. | |
| Dec 18, 2019 at 20:58 | history | edited | GentlePurpleRain | CC BY-SA 4.0 |
edited body
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| Dec 18, 2019 at 20:47 | history | answered | Neil | CC BY-SA 4.0 |