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Apr 10, 2022 at 12:19 comment added Daniel Mathias @FlorianF Placing 2 and 6 next to 20 puts 16 and 12 on their respective vertices, leaving 14 and 18 on the remaining side needing the 6 again for 38. Your logic leading to 20-2-16-10-12 leaves only one place for 18, proving the solution unique.
Apr 10, 2022 at 10:13 comment added Florian F Placing 2 and 4 next to 20 is a bit arbitrary. Why not 2 and 6? Couldn't it also work? You could have started more logically by noting that 2 can only be in a line with 20 and 16 and 10 only with 12 and 16.
Oct 15, 2019 at 4:00 comment added SamRoy Nice approach. +1
Oct 13, 2019 at 19:04 history answered Daniel Mathias CC BY-SA 4.0