Return to Answer

added 8 characters in body

Source Link

edited Mar 26, 2019 at 14:07

Arnaud Mortier

7.5k
22
55

The answer could be

ESTER

Which I believe would mean that

Your wife has chosen a name for the baby.

For the reason that

The first of these Tuesdays is the 11th tuesday of the year; the second is the 25th, and so on resulting in the sequence: $$11 25 26 37 50$$$$11\, 25\, 26\, 37\, 50$$ If you set $$1=A, 2=B,\ldots, 26=Z,\qquad 27=A, 28=B,\ldots$$ this gives the word $$KYZKX$$ which after a $-6$ Caesar shift gives $ESTER$.

The answer could be

ESTER

Which I believe would mean that

Your wife has chosen a name for the baby.

For the reason that

The first of these Tuesdays is the 11th tuesday of the year; the second is the 25th, and so on resulting in the sequence: $$11 25 26 37 50$$ If you set $$1=A, 2=B,\ldots, 26=Z,\qquad 27=A, 28=B,\ldots$$ this gives the word $$KYZKX$$ which after a $-6$ Caesar shift gives $ESTER$.

The answer could be

ESTER

Which I believe would mean that

Your wife has chosen a name for the baby.

For the reason that

The first of these Tuesdays is the 11th tuesday of the year; the second is the 25th, and so on resulting in the sequence: $$11\, 25\, 26\, 37\, 50$$ If you set $$1=A, 2=B,\ldots, 26=Z,\qquad 27=A, 28=B,\ldots$$ this gives the word $$KYZKX$$ which after a $-6$ Caesar shift gives $ESTER$.

Source Link

created Mar 26, 2019 at 13:45

Arnaud Mortier

7.5k
22
55

The answer could be

ESTER

Which I believe would mean that

Your wife has chosen a name for the baby.

For the reason that

The first of these Tuesdays is the 11th tuesday of the year; the second is the 25th, and so on resulting in the sequence: $$11 25 26 37 50$$ If you set $$1=A, 2=B,\ldots, 26=Z,\qquad 27=A, 28=B,\ldots$$ this gives the word $$KYZKX$$ which after a $-6$ Caesar shift gives $ESTER$.