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Dmihawk
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Is the answer 02/03/1700?

Four days before that would be 26/02/1700. The month has 2 distinct prime divisors, 2 and 13, one of which is the month.

The only part of the calendar which differs from year to year is 29/02. So the 4 day stretch must span this date, if it is true that the year can be deduced by the day.

Years divisible by 100, but not 400, do not have a leap day. Of the numbers {25, 26, 27, 28, 29}, only 26 has distinct prime divisors. And 4 days ahead of 26/02 is 02/03, in a non-leap year.

The next question is the century. But the second paragraph states that the riddles were published in the 18th century (ie., the 1700s). If the Captain was alive during the 1700s then only the year 1700 makes sense.

As for the language, that has me stumped. :)

02/03/1700?

Four days before that would be 26/02/1700. The month has 2 distinct prime divisors, 2 and 13, one of which is the month.

The only part of the calendar which differs from year to year is 29/02. So the 4 day stretch must span this date, if it is true that the year can be deduced by the day.

Years divisible by 100, but not 400, do not have a leap day. Of the numbers {25, 26, 27, 28, 29}, only 26 has distinct prime divisors. And 4 days ahead of 26/02 is 02/03, in a non-leap year.

The next question is the century. But the second paragraph states that the riddles were published in the 18th century (ie., the 1700s). If the Captain was alive during the 1700s then only the year 1700 makes sense.

As for the language, that has me stumped. :)

Is the answer 02/03/1700?

Four days before that would be 26/02/1700. The month has 2 distinct prime divisors, 2 and 13, one of which is the month.

The only part of the calendar which differs from year to year is 29/02. So the 4 day stretch must span this date, if it is true that the year can be deduced by the day.

Years divisible by 100, but not 400, do not have a leap day. Of the numbers {25, 26, 27, 28, 29}, only 26 has distinct prime divisors. And 4 days ahead of 26/02 is 02/03, in a non-leap year.

The next question is the century. But the second paragraph states that the riddles were published in the 18th century (ie., the 1700s). If the Captain was alive during the 1700s then only the year 1700 makes sense.

As for the language, that has me stumped. :)

Is the answer:

02/03/1700?

Four days before that would be 26/02/1700. The month has 2 distinct prime divisors, 2 and 13, one of which is the month.

The only part of the calendar which differs from year to year is 29/02. So the 4 day stretch must span this date, if it is true that the year can be deduced by the day.

Years divisible by 100, but not 400, do not have a leap day. Of the numbers {25, 26, 27, 28, 29}, only 26 has distinct prime divisors. And 4 days ahead of 26/02 is 02/03, in a non-leap year.

The next question is the century. But the second paragraph states that the riddles were published in the 18th century (ie., the 1700s). If the Captain was alive during the 1700s then only the year 1700 makes sense.

As for the language, that has me stumped. :)

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Is the answer 02/03/1700?

Four days before that would be 26/02/1700. The month has 2 distinct prime divisors, 2 and 13, one of which is the month.

The only part of the calendar which differs from year to year is 29/02. So the 4 day stretch must span this date, if it is true that the year can be deduced by the day.

Years divisible by 100, but not 400, do not have a leap day. Of the numbers {25, 26, 27, 28, 29}, only 26 has distinct prime divisors. And 4 days ahead of 26/02 is 02/03, in a non-leap year.

The next question is the century. But the second paragraph states that the riddles were published in the 18th century (ie., the 1700s). If the Captain was alive during the 1700s then only the year 1700 makes sense.

As for the language, that has me stumped. :)