Timeline for How do I make 76 using only the numbers 2,0,1,9?
Current License: CC BY-SA 4.0
11 events
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| Dec 12, 2018 at 8:15 | history | edited | TakingNotes | CC BY-SA 4.0 |
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| Dec 11, 2018 at 20:37 | history | edited | TakingNotes | CC BY-SA 4.0 |
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| Dec 11, 2018 at 20:31 | history | edited | TakingNotes | CC BY-SA 4.0 |
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| Dec 11, 2018 at 16:32 | comment | added | TakingNotes | Yes, thank you for pointing out my error. I had taken the Sloane/Pouffe definition of superfactorial(4) and divided it by 4, not 24. Thankyou for pointing that out. | |
| Dec 11, 2018 at 16:30 | comment | added | Excited Raichu | By the Pickover definition, the superfactorial of 3 is about 10^10^10^10^36000. By the Sloane/Plouffe definition, the superfactorial of 3 is 12, or if you're counting 0, 2. Neither of them are 72. | |
| Dec 11, 2018 at 16:23 | history | edited | TakingNotes | CC BY-SA 4.0 |
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| Dec 11, 2018 at 16:23 | comment | added | rhsquared | Isn't the square root implicitly using an extra digit 2? Because sqrt that is (x)^1/2 | |
| Dec 11, 2018 at 16:20 | history | edited | TakingNotes | CC BY-SA 4.0 |
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| S Dec 11, 2018 at 16:19 | history | suggested | S. M. | CC BY-SA 4.0 |
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| Dec 11, 2018 at 16:18 | review | Suggested edits | |||
| S Dec 11, 2018 at 16:19 | |||||
| Dec 11, 2018 at 16:17 | history | answered | TakingNotes | CC BY-SA 4.0 |