Timeline for 100 using only 5 number of digits
Current License: CC BY-SA 4.0
15 events
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| Oct 18, 2018 at 13:03 | comment | added | maxathousand | @GeorgeMenoutis "Someone else could say that the zeroes of "00.d000" are still there." That was the point I was trying to make :) All I was saying was that the padding of zeroes shouldn't reduce this answer's validity because padding with 0 or 500 zeroes in either direction doesn't change the value. | |
| Oct 18, 2018 at 11:09 | comment | added | George Menoutis | @maxathousand I disagree. Both notations .5 and 0.5 are used around the world. I would vote "better" the one who is less arbitrary. The 0 in 0.5 is generally easier to spot by the eye, but .5 is well-defined too. Having said this, it is a fact that all zeroes included in the prefix and the suffix of a number are useless. You say that in .d the zero is "still there" - Someone else could say that the zeroes of "00.d000" are still there. | |
| Oct 10, 2018 at 13:37 | comment | added | Rycochet | @chux doh - I forgot that bit of it! :-P | |
| Oct 10, 2018 at 13:25 | comment | added | Battle |
@maxathousand - The .d is a typically US notation for values which are 0.d. Officially the zero is there. A made up notation could be: 10 = 1', for 100 = 1'', 1000 = 1'''. Sure, you are leaving out writing down the zeroes for 1''', but it's still 1000, just as .1 = 0.1. It's a nice answer, if it weren't for this.
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| Oct 10, 2018 at 13:24 | comment | added | chux |
@Rycochet (nnn - nn) / n is simpler, yet uses 6 n, not "only 5 number of digits"
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| Oct 10, 2018 at 13:17 | comment | added | Rycochet |
Or even simpler - (nnn - nn) / n
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| Oct 9, 2018 at 15:40 | comment | added | Jack Aidley | @chux: I find that an unconvincing argument, but since the Asker's specification is vague I shan't pursue the point further. your solution is certainly clever. | |
| Oct 9, 2018 at 15:29 | comment | added | chux | @JackAidley re: point counts as an operation?: As OP used 3 digits as "111", it implies textual concentration is a legal operation. Concatenation to the right of the decimal point is just the next step. | |
| Oct 9, 2018 at 14:17 | comment | added | maxathousand | @rhsquared Arguably, any integer $x$ is actually $x.0$.. ;) | |
| Oct 9, 2018 at 12:39 | comment | added | rhsquared | This solution is very nice but the usage of decimal point implicitly uses a 0, because .7 is actually 0.7. | |
| Oct 9, 2018 at 11:33 | history | edited | u-ndefined | CC BY-SA 4.0 |
MathJax
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| Oct 9, 2018 at 8:55 | comment | added | Jack Aidley | I wonder whether the use of a decimal point counts as an operation? | |
| Oct 8, 2018 at 23:31 | history | edited | chux | CC BY-SA 4.0 |
added 15 characters in body
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| Oct 8, 2018 at 23:27 | comment | added | Weather Vane | Nicely done. Universal solution. | |
| Oct 8, 2018 at 23:22 | history | answered | chux | CC BY-SA 4.0 |