$ ((0! + 0!)\\\$)*(0! + 0!) = 2^2*2 = 8 $. Where the \$ operation denotes the superfactorial defined as: $ n\\\$ = (n!) \uparrow \uparrow (n!)$

$ ((0! + 0!)\\\$)*(0! + 0!) = 2^2*2 = 8 $.

Further explanation:

The $\\\$$ operation denotes the superfactorial defined as  : $ n\\\$ = (n!) \uparrow \uparrow (n!)$.

$$ ((0! + 0!)$)*(0! + 0!) = 2^2*2 = 8 $$

Where the \$ operation denotes the superfactorial defined as: $$ n\\\$ = (n!) \uparrow \uparrow (n!)$$

$ ((0! + 0!)\\\$)*(0! + 0!) = 2^2*2 = 8 $. Where the \$ operation denotes the superfactorial defined as: $ n\\\$ = (n!) \uparrow \uparrow (n!)$