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New theory!

Moving my comments into a partial answer so that I can edit it as I go and not extend the discussion for it in Oleg's answer.

We know from the first hint and the bounty text that:

We need to substitute one (or more) of the characters in the error code.

With the new hint:

If we replace all the numbers with "1" and all the letters with "0", we get 110010100

Which is:

The number "404" when converted from decimal. Which just so happens to be the infamous HTTP error response code for page not found!

So:

You might want to fix your page indexes to make sure you don't lose your job!

New theory!

Moving my comments into a partial answer so that I can edit it as I go and not extend the discussion for it in Oleg's answer.

We know from the first hint and the bounty text that:

We need to substitute one (or more) of the characters in the error code.

With the new hint:

If we replace all the numbers with "1" and all the letters with "0", we get 110010100

Which is:

The number "404" when converted to decimal. Which just so happens to be the infamous HTTP error response code for page not found!

So:

You might want to fix your page indexes to make sure you don't lose your job!

Partial Answer:

Moving my comments into a partial answer so that I can edit it as I go and not extend the discussion for it in Oleg's answer.

We know from the first hint and the bounty text that:

We need to substitute one (or more) of the characters in the error code.

My current thinking is that:

Given the use of "change a few variables" (numbers can't be variables in most programming languages) and "(current fix is br0ken)" where the 'o' has been turned into a '0', my suspicion is that we are converting the letters into numbers.

Which leads to:

If we substitute each letter in the error code with its position in the alphabet, we get "321655831".

The second hint points toward:

Converting our value into binary format.

The decimal value 321,655,831 when represented in binary is: 00010011 00101100 00010100 00010111 (I've broken it into bytes for ease of reading).

The current challenge:

Reading each of the four bytes as individual numbers gives us 19, 44, 20 and 23, which is out of range for the alphabet (thanks to the 44) and too small for ASCII values (the uppercase alphabet starts at 65). I shall think on this some more, but feel free to steal the credit thus far if you can extend the progress on the solution!

New hypothesis:

If we take the four numbers (19, 44, 20 and 23) and map them back to characters. We can get S, R, T and W (this works if we take 44 - 26 = 18). It's too short to be be part of an imgur URL though...

New theory!

Moving my comments into a partial answer so that I can edit it as I go and not extend the discussion for it in Oleg's answer.

We know from the first hint and the bounty text that:

We need to substitute one (or more) of the characters in the error code.

With the new hint:

If we replace all the numbers with "1" and all the letters with "0", we get 110010100

Which is:

The number "404" when converted from decimal. Which just so happens to be the infamous HTTP error response code for page not found!

So:

You might want to fix your page indexes to make sure you don't lose your job!

Partial Answer:

Moving my comments into a partial answer so that I can edit it as I go and not extend the discussion for it in Oleg's answer.

We know from the first hint and the bounty text that:

We need to substitute one (or more) of the characters in the error code.

My current thinking is that:

Given the use of "change a few variables" (numbers can't be variables in most programming languages) and "(current fix is br0ken)" where the 'o' has been turned into a '0', my suspicion is that we are converting the letters into numbers.

Which leads to:

If we substitute each letter in the error code with its position in the alphabet, we get "321655831".

The second hint points toward:

Converting our value into binary format.

The decimal value 321,655,831 when represented in binary is: 00010011 00101100 00010100 00010111 (I've broken it into bytes for ease of reading).

The current challenge:

Reading each of the four bytes as individual numbers gives us 19, 44, 20 and 23, which is out of range for the alphabet (thanks to the 44) and too small for ASCII values (the uppercase alphabet starts at 65). I shall think on this some more, but feel free to steal the credit thus far if you can extend the progress on the solution!

Partial Answer:

Moving my comments into a partial answer so that I can edit it as I go and not extend the discussion for it in Oleg's answer.

We know from the first hint and the bounty text that:

We need to substitute one (or more) of the characters in the error code.

My current thinking is that:

Given the use of "change a few variables" (numbers can't be variables in most programming languages) and "(current fix is br0ken)" where the 'o' has been turned into a '0', my suspicion is that we are converting the letters into numbers.

Which leads to:

If we substitute each letter in the error code with its position in the alphabet, we get "321655831".

The second hint points toward:

Converting our value into binary format.

The decimal value 321,655,831 when represented in binary is: 00010011 00101100 00010100 00010111 (I've broken it into bytes for ease of reading).

The current challenge:

Reading each of the four bytes as individual numbers gives us 19, 44, 20 and 23, which is out of range for the alphabet (thanks to the 44) and too small for ASCII values (the uppercase alphabet starts at 65). I shall think on this some more, but feel free to steal the credit thus far if you can extend the progress on the solution!

New hypothesis:

If we take the four numbers (19, 44, 20 and 23) and map them back to characters. We can get S, R, T and W (this works if we take 44 - 26 = 18). It's too short to be be part of an imgur URL though...