I got this one.

Captain was born in 1 9 9 3
He will be 1 3 years old, a canonical age, in 2 0 0 6
In this text, There is only 6 different digits, each of them being used 2 times

I will write how to achieve that soon.

Nb. To be honest, I don't exactly know what is the definition of canonical age.

I got this one.

Captain was born in 1 9 9 3
He will be 1 3 years old, a canonical age, in 2 0 0 6
In this text, There is only 6 different digits, each of them being used 2 times

How I achieve that?

At first, I assume that the Captain was born in 1 9 A B and will be on canonical age in 2 0 C D because the script was written in 1999.

We already have 4 different digits here, but writing 4 means we have 5 different digits. So there is a total of 6 different digits here, and each of them being used 2 times. (5 is impossible because the number of . is not divisible by 5).

So now we have 1 9 A B + E F = 2 0 C D, and we know that ABCDEF can be 0169XX. By some deduction, we can know that 0 can only replace C. And then, I was trying to put A = 9 and E = 1 the leaving BDF to be 6XX so X will be 3. Finally, the solution I arrive here is 1 9 9 3 + 1 3 = 2 0 0 6.

Nb. To be honest, I don't exactly know what is the definition of canonical age.