Timeline for A different kind of weighing problem
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 18, 2017 at 21:31 | comment | added | J Mark Inman | >For example there is no weighing in which only one of the two coins that make up e appears. // I see what you mean! | |
| Oct 18, 2017 at 20:13 | comment | added | Laska | If I’ve understood you properly, then I don’t think your solution can work. For example there is no weighing in which only one of the two coins that make up e appears. So if one is x and one is y, we can’t tell which is which. By the way in my own thinking, I have always been assuming that one weighing is never a strict subset of another so e.g. I would never weigh 7 and then 5 but instead 2 and then 5. It’s equivalent but simpler. | |
| Oct 18, 2017 at 15:03 | review | First posts | |||
| Oct 18, 2017 at 16:12 | |||||
| Oct 18, 2017 at 15:02 | history | answered | J Mark Inman | CC BY-SA 3.0 |