Timeline for Batman vs 4 villains
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 20, 2017 at 12:07 | comment | added | Flater | @Apep: true, but that does have some implications for questions such as "Does Penguin answer before Two-Face?", where Batman must observe the original round order as opposed to his changed round order. | |
| Sep 20, 2017 at 11:59 | comment | added | Apep | @Flater It works under the assumption that Batman does not have to ask the same question 4 times. The 'rounds' was those set up in the answer (asking the same question 4 times), not those in the question (the villains answering in order). Once the Joker is found, Batman can stop asking the first question and ask the second question 4 times. In the case that the Joker is not the 4th, this saves at least one question. In the case that the Joker is the 4th, Batman does not need to ask him the last question, so that also saves one question. | |
| Sep 20, 2017 at 8:15 | comment | added | Flater | @Apep (and Braydon): Does your comment work under the assumption that Batman can ask to skip to the next round? As it was described, it's a sequence of ask-answer-pass-repeat (and any deviation from this will end in losing the game), so it may be impossible to "skip ahead". | |
| Sep 19, 2017 at 14:20 | comment | added | Braydon | @dqwertyC This answer can actually be much faster if the Joker goes first, as he will identify himself and there is no need to ask the next 3 pass questions. | |
| Sep 19, 2017 at 12:18 | comment | added | Samthere | The problem is that if they "no" to your first question, it probably becomes true. I'm not certain about this but I think it makes sense. | |
| Sep 19, 2017 at 6:32 | comment | added | Braydon | @oobug Oh yes, new rules were added after I had posted my answer, hurray for changing puzzle rules. | |
| Sep 19, 2017 at 5:53 | comment | added | oobug | @DqwertyC I don't think your first question is cheap. Batman could ask them "Is my right index finger itchy?" and it would be an equally valid question. | |
| Sep 19, 2017 at 5:52 | comment | added | oobug | @Braydon the puzzle clearly states that the Joker will never pass. | |
| Sep 19, 2017 at 2:30 | comment | added | Braydon | @Saladani How is the Joker answering to mess with you if he allows himself to be found by refusing to pass? If he wants to mess up Batman he should pass. If this is an acceptable answer the question was again unclear. | |
| Sep 19, 2017 at 0:38 | comment | added | Saladani | +1 for the work so far. I may add a second bonus where a villain hangs-up if he is asked a question he cannot answer, but this answer is valid for the problem as stated | |
| Sep 19, 2017 at 0:30 | comment | added | Apep | You could reduce the number of questions by at least one. If the Joker is the last, he is not required for the last round of questions. If he is not last, you can start the second round of questions at least one question earlier. | |
| Sep 19, 2017 at 0:24 | history | answered | DqwertyC | CC BY-SA 3.0 |