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wording tweak.
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DKATyler
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Send the first#0 kamikaze forward 2 spaces (spaces 1,3)
If If he lives, then we're in the first 8 scenarios from M Oehm's answer. If he's he's dead, it's the last 8 scenarios. Since the 2 options are mirror images. I'll just paste the first 8: Upper 8 Possibilities

To solveFor the remaining 8, it's simple enough to just send a kamikaze towhen visited from the end, then try top row exactly one space less until we don't hear himof the squares marked in yellow will not result in a scream. May as well check them in order. First kami scout is "lucky" and has 5/8 where he stays alive.
So: 2nd kamikaze goes all 5 spaces (top if scout1 lived, bottom otherwise). $40, 10/16. 3rd kamikaze goes 4 spaces same manner. $60, 2/16 4th kamikaze goes 3 spaces. $80, 2/16 No need for the 5th kami since the very first scout did that job.Test Order
`So:

  1. kamikaze goes all 5 spaces $40 total, 5/8.
  2. kamikaze goes 4 spaces then down 1. $60, 1/8
  3. kamikaze goes 3 spaces then down 1. $80, 1/8 The last yellow square is the answer if the #3 kami screamed. $80, 1/8 Total cost: ($40 * 5/8 + $60 * 1/8 + $80 * 1/8 + $80 * 1/8) = $52.50`
    Note: If a happy-go-lucky was willing to work for 1 penny less, I could use a happy in-place of the first/second kamikaze. Half the time he'd survive to use his second order (save \$10). Half the time he wouldn't (extra \$10 cost).

SoDespite using all kamikazes, the total expected cost in lives is surprisingly "low":
$40 * 10/16 + $60 * 2/16 + $80 * 4/16 = $52.50`0. kami: 50-50 survival odds (4/8 chance of death)

  1. kami: 5/8 survival odds (3/8 chance of death)
  2. kami: 5/8 + 1/8 = 6/8 (2/8 chance of death)
  3. kami: 6/8 + 1/8 = 7/8 (1/8 chance of death) Expected casualties is: 10/8 = 1.25`

**Bonus 2**Very similar to the base scenario, but test only the bottom 3 yellow squares.[![Bonus 2 order][3]][3]Cost is:`$40 2/8$60 2/8$80 4/8= $65`

And the lives lost is surprisingly "low":
1st kami: 8/16 survival odds (4/8 chance of death) 2nd kami: 5/8 survival odds (3/8 chance of death) 3rd kami: 5/8 + 1/8 = 6/8 (2/8 chance of death) 4th kami: 6/8 + 1/8 = 7/8 (1/8 chance of death)
So expected casualties is`0. kami: 10/8 = 1.25 50-50 survival odds (4/8 chance of death)

  1. kami: 2/8 survival odds (6/8 chance of death)
  2. kami: 2/8 + 2/8 = 4/8 (4/8 chance of death)
  3. kami: 4/8 + 2/8 = 6/8 (2/8 chance of death) You: 7/8 (1/8 chance of death) Expected Casualties is: 17/8 = 2.125`
    Warning: You want the #1 kamikaze dead (2nd one sent). If he survives you're stuck with a choice, pay a scout $20 to take the 50-50 risk of death for treasure. Or do it yourself. Since you're nearly bankrupt, what have you got to lose?
    Are you feeling lucky?

Send the first kamikaze forward 2 spaces (spaces 1,3)
If he lives, then we're in the first 8 scenarios from M Oehm's answer. If he's dead, it's the last 8 scenarios.

To solve the remaining 8, it's simple enough to just send a kamikaze to the end, then try one space less until we don't hear him scream.
So: 2nd kamikaze goes all 5 spaces (top if scout1 lived, bottom otherwise). $40, 10/16. 3rd kamikaze goes 4 spaces same manner. $60, 2/16 4th kamikaze goes 3 spaces. $80, 2/16 No need for the 5th kami since the very first scout did that job.

So the total expected cost is:
$40 * 10/16 + $60 * 2/16 + $80 * 4/16 = $52.50

And the lives lost is surprisingly "low":
1st kami: 8/16 survival odds (4/8 chance of death) 2nd kami: 5/8 survival odds (3/8 chance of death) 3rd kami: 5/8 + 1/8 = 6/8 (2/8 chance of death) 4th kami: 6/8 + 1/8 = 7/8 (1/8 chance of death)
So expected casualties is: 10/8 = 1.25

Send the #0 kamikaze forward 2 spaces (spaces 1,3) If he lives, then we're in the first 8 scenarios from M Oehm's answer. If he's dead, it's the last 8 scenarios. Since the 2 options are mirror images. I'll just paste the first 8: Upper 8 Possibilities

For the remaining 8, when visited from the top row exactly one of the squares marked in yellow will not result in a scream. May as well check them in order. First kami scout is "lucky" and has 5/8 where he stays alive.
Test Order
`So:

  1. kamikaze goes all 5 spaces $40 total, 5/8.
  2. kamikaze goes 4 spaces then down 1. $60, 1/8
  3. kamikaze goes 3 spaces then down 1. $80, 1/8 The last yellow square is the answer if the #3 kami screamed. $80, 1/8 Total cost: ($40 * 5/8 + $60 * 1/8 + $80 * 1/8 + $80 * 1/8) = $52.50`
    Note: If a happy-go-lucky was willing to work for 1 penny less, I could use a happy in-place of the first/second kamikaze. Half the time he'd survive to use his second order (save \$10). Half the time he wouldn't (extra \$10 cost).

Despite using all kamikazes, the cost in lives is surprisingly "low":
`0. kami: 50-50 survival odds (4/8 chance of death)

  1. kami: 5/8 survival odds (3/8 chance of death)
  2. kami: 5/8 + 1/8 = 6/8 (2/8 chance of death)
  3. kami: 6/8 + 1/8 = 7/8 (1/8 chance of death) Expected casualties is: 10/8 = 1.25`

**Bonus 2**Very similar to the base scenario, but test only the bottom 3 yellow squares.[![Bonus 2 order][3]][3]Cost is:`$40 2/8$60 2/8$80 4/8= $65`

And the lives lost is:
`0. kami: 50-50 survival odds (4/8 chance of death)

  1. kami: 2/8 survival odds (6/8 chance of death)
  2. kami: 2/8 + 2/8 = 4/8 (4/8 chance of death)
  3. kami: 4/8 + 2/8 = 6/8 (2/8 chance of death) You: 7/8 (1/8 chance of death) Expected Casualties is: 17/8 = 2.125`
    Warning: You want the #1 kamikaze dead (2nd one sent). If he survives you're stuck with a choice, pay a scout $20 to take the 50-50 risk of death for treasure. Or do it yourself. Since you're nearly bankrupt, what have you got to lose?
    Are you feeling lucky?
Source Link
DKATyler
  • 226
  • 1
  • 4

Kamikazes all the way.

Send the first kamikaze forward 2 spaces (spaces 1,3)
If he lives, then we're in the first 8 scenarios from M Oehm's answer. If he's dead, it's the last 8 scenarios.

To solve the remaining 8, it's simple enough to just send a kamikaze to the end, then try one space less until we don't hear him scream.
So: 2nd kamikaze goes all 5 spaces (top if scout1 lived, bottom otherwise). $40, 10/16. 3rd kamikaze goes 4 spaces same manner. $60, 2/16 4th kamikaze goes 3 spaces. $80, 2/16 No need for the 5th kami since the very first scout did that job.

So the total expected cost is:
$40 * 10/16 + $60 * 2/16 + $80 * 4/16 = $52.50

And the lives lost is surprisingly "low":
1st kami: 8/16 survival odds (4/8 chance of death) 2nd kami: 5/8 survival odds (3/8 chance of death) 3rd kami: 5/8 + 1/8 = 6/8 (2/8 chance of death) 4th kami: 6/8 + 1/8 = 7/8 (1/8 chance of death)
So expected casualties is: 10/8 = 1.25