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Sep 3, 2020 at 23:11 comment added Glen O @Shufflepants - at no point did I say that my algorithm is optimal, just that it is likely to be more efficient than the one proposed in the question in many situations. I decided against explicitly discussing the logical extension of the algorithm to $n$-step, which will always find the optimal solution so long as $n$ is greater than or equal to the length of the optimal solution, and is likely to find the optimal solution as long as $n$ is sufficiently large.
Aug 13, 2019 at 19:16 comment added Shufflepants Mike's comment on the question would seem disprove this conjecture.
Jan 14, 2017 at 14:29 vote accept Rand al'Thor
Dec 13, 2016 at 7:29 history answered Glen O CC BY-SA 3.0