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Kokiomot
Kokiomot
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There are an awful lot of 0s, so it seems reasonable to me to use them as a delimiter. Replacing them with commas yields this sequence: 26,5,4,4,14,4,63,256,,1,3,256,,1,3,3,2,56,5,16,4,13,256,,4,4,,1,3,256,,1,56,,13,256,4,13,,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13,,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256,,1,3,256,,4,4,,1,3,26,4,4,63,2,56,,6,6,6,13,3,256,5,14,1,3,256,,4,4,,1,3,3,256,,1,56,,13,2,56,6,4,4,13, On a hunch,

On a hunch,

I've put in spaces wherever there were two zeros in a row: 26,5,4,4,14,4,63,256, ,1,3,256, ,1,3,3,2,56,5,16,4,13,256, ,4,4, ,1,3,256, ,1,56, ,13,256,4,13, ,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13, ,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256, ,1,3,256, ,4,4, ,1,3,26,4,4,63,2,56, ,6,6,6,13,3,256,5,14,1,3,256, ,4,4, ,1,3,3,256, ,1,56, ,13,2,56,6,4,4,13 Excluding spaces, this gives us the following

Excluding spaces, this gives us the following

13 unique numbers:    1, 2, 3, 4, 5, 6, 13, 14, 16, 26, 56, 63, 256 There's only the digits 0-6 in the sequence, which could be

There's only the digits 0-6 in the sequence, which could be

base 7. That means the decimal numbers are: 1, 2, 3, 4, 5, 6, 10, 11, 13, 20, 41, 45, 139 However, that sequence doesn't mean anything to me. Then I remembered that

However, that sequence doesn't mean anything to me. Then again,

I removed all the 0s, using them for delimiters, which means the only valid digits remaining are 1-6. Maybe it's base 6, where 1 maps to 0, 2 to 1, etc? 0, 1, 2, 3, 4, 5, 2*, 3*, 6*, 11, 29, 32, 65 That doesn't make much sense, though, since the starred numbers would have a leading 0, which would be unnessesary. 13

That doesn't make much sense, though, since the starred numbers would have a leading 0, which would be unnessesary.

Perhaps a cryptogram?

13 different numbers doesn't seem too strange for a cryptogramthat, so I made the following substitutions: 1=A, 2=B, 3=C, 4=D, 5=E, 6=F, 13=G, 14=H, 16=I, 26=J, 56=K, 63=L, 256=M. That gives us this potential cryptogram: JEDDHDLM

That gives us this potential cryptogram:

JEDDHDLM ACM ACCBKEIDGM DD ACM AK GMDG CMEHDACJEDDHDLBKFDDGMEDHACCJEDDHDLMDG MEDHACCMEHDACMEDHACM ACM DD ACJDDLBK FFFGCMEHACM DD ACCM AK GBKFDDG. However, there are some awfully long words in there, as well as a repeated word "DD", and a word starting "FFF", which I don't believe can be translated.

There are an awful lot of 0s, so it seems reasonable to me to use them as a delimiter. Replacing them with commas yields this sequence: 26,5,4,4,14,4,63,256,,1,3,256,,1,3,3,2,56,5,16,4,13,256,,4,4,,1,3,256,,1,56,,13,256,4,13,,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13,,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256,,1,3,256,,4,4,,1,3,26,4,4,63,2,56,,6,6,6,13,3,256,5,14,1,3,256,,4,4,,1,3,3,256,,1,56,,13,2,56,6,4,4,13, On a hunch, I've put in spaces wherever there were two zeros in a row: 26,5,4,4,14,4,63,256, ,1,3,256, ,1,3,3,2,56,5,16,4,13,256, ,4,4, ,1,3,256, ,1,56, ,13,256,4,13, ,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13, ,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256, ,1,3,256, ,4,4, ,1,3,26,4,4,63,2,56, ,6,6,6,13,3,256,5,14,1,3,256, ,4,4, ,1,3,3,256, ,1,56, ,13,2,56,6,4,4,13 Excluding spaces, this gives us the following 13 unique numbers:  1, 2, 3, 4, 5, 6, 13, 14, 16, 26, 56, 63, 256 There's only the digits 0-6 in the sequence, which could be base 7. That means the decimal numbers are: 1, 2, 3, 4, 5, 6, 10, 11, 13, 20, 41, 45, 139 However, that sequence doesn't mean anything to me. Then I remembered that I removed all the 0s, using them for delimiters, which means the only valid digits remaining are 1-6. Maybe it's base 6, where 1 maps to 0, 2 to 1, etc? 0, 1, 2, 3, 4, 5, 2*, 3*, 6*, 11, 29, 32, 65 That doesn't make much sense, though, since the starred numbers would have a leading 0, which would be unnessesary. 13 different numbers doesn't seem too strange for a cryptogram, so I made the following substitutions: 1=A, 2=B, 3=C, 4=D, 5=E, 6=F, 13=G, 14=H, 16=I, 26=J, 56=K, 63=L, 256=M. That gives us this potential cryptogram: JEDDHDLM ACM ACCBKEIDGM DD ACM AK GMDG CMEHDACJEDDHDLBKFDDGMEDHACCJEDDHDLMDG MEDHACCMEHDACMEDHACM ACM DD ACJDDLBK FFFGCMEHACM DD ACCM AK GBKFDDG However, there are some awfully long words in there, as well as a repeated word "DD", and a word starting "FFF", which I don't believe can be translated.

There are an awful lot of 0s, so it seems reasonable to me to use them as a delimiter. Replacing them with commas yields this sequence: 26,5,4,4,14,4,63,256,,1,3,256,,1,3,3,2,56,5,16,4,13,256,,4,4,,1,3,256,,1,56,,13,256,4,13,,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13,,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256,,1,3,256,,4,4,,1,3,26,4,4,63,2,56,,6,6,6,13,3,256,5,14,1,3,256,,4,4,,1,3,3,256,,1,56,,13,2,56,6,4,4,13,

On a hunch,

I've put in spaces wherever there were two zeros in a row: 26,5,4,4,14,4,63,256, ,1,3,256, ,1,3,3,2,56,5,16,4,13,256, ,4,4, ,1,3,256, ,1,56, ,13,256,4,13, ,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13, ,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256, ,1,3,256, ,4,4, ,1,3,26,4,4,63,2,56, ,6,6,6,13,3,256,5,14,1,3,256, ,4,4, ,1,3,3,256, ,1,56, ,13,2,56,6,4,4,13

Excluding spaces, this gives us the following

13 unique numbers:  1, 2, 3, 4, 5, 6, 13, 14, 16, 26, 56, 63, 256

There's only the digits 0-6 in the sequence, which could be

base 7. That means the decimal numbers are: 1, 2, 3, 4, 5, 6, 10, 11, 13, 20, 41, 45, 139

However, that sequence doesn't mean anything to me. Then again,

I removed all the 0s, using them for delimiters, which means the only valid digits remaining are 1-6. Maybe it's base 6, where 1 maps to 0, 2 to 1, etc? 0, 1, 2, 3, 4, 5, 2*, 3*, 6*, 11, 29, 32, 65

That doesn't make much sense, though, since the starred numbers would have a leading 0, which would be unnessesary.

Perhaps a cryptogram?

13 different numbers doesn't seem too strange for that, so I made the following substitutions: 1=A, 2=B, 3=C, 4=D, 5=E, 6=F, 13=G, 14=H, 16=I, 26=J, 56=K, 63=L, 256=M.

That gives us this potential cryptogram:

JEDDHDLM ACM ACCBKEIDGM DD ACM AK GMDG CMEHDACJEDDHDLBKFDDGMEDHACCJEDDHDLMDG MEDHACCMEHDACMEDHACM ACM DD ACJDDLBK FFFGCMEHACM DD ACCM AK GBKFDDG. However, there are some awfully long words in there, as well as a repeated word "DD", and a word starting "FFF", which I don't believe can be translated.

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Kokiomot
Kokiomot
  • 561
  • 5
  • 6

This is a partial attempt, but I think I may be on the right track.

There are an awful lot of 0s, so it seems reasonable to me to use them as a delimiter. Replacing them with commas yields this sequence: 26,5,4,4,14,4,63,256,,1,3,256,,1,3,3,2,56,5,16,4,13,256,,4,4,,1,3,256,,1,56,,13,256,4,13,,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13,,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256,,1,3,256,,4,4,,1,3,26,4,4,63,2,56,,6,6,6,13,3,256,5,14,1,3,256,,4,4,,1,3,3,256,,1,56,,13,2,56,6,4,4,13, On a hunch, I've put in spaces wherever there were two zeros in a row: 26,5,4,4,14,4,63,256, ,1,3,256, ,1,3,3,2,56,5,16,4,13,256, ,4,4, ,1,3,256, ,1,56, ,13,256,4,13, ,3,256,5,14,4,1,3,26,5,4,4,14,4,63,2,56,6,4,4,13,256,5,4,14,1,3,3,26,5,4,4,14,4,63,256,4,13, ,256,5,4,14,1,3,3,256,5,14,4,1,3,256,5,4,14,1,3,256, ,1,3,256, ,4,4, ,1,3,26,4,4,63,2,56, ,6,6,6,13,3,256,5,14,1,3,256, ,4,4, ,1,3,3,256, ,1,56, ,13,2,56,6,4,4,13 Excluding spaces, this gives us the following 13 unique numbers: 1, 2, 3, 4, 5, 6, 13, 14, 16, 26, 56, 63, 256 There's only the digits 0-6 in the sequence, which could be base 7. That means the decimal numbers are: 1, 2, 3, 4, 5, 6, 10, 11, 13, 20, 41, 45, 139 However, that sequence doesn't mean anything to me. Then I remembered that I removed all the 0s, using them for delimiters, which means the only valid digits remaining are 1-6. Maybe it's base 6, where 1 maps to 0, 2 to 1, etc? 0, 1, 2, 3, 4, 5, 2*, 3*, 6*, 11, 29, 32, 65 That doesn't make much sense, though, since the starred numbers would have a leading 0, which would be unnessesary. 13 different numbers doesn't seem too strange for a cryptogram, so I made the following substitutions: 1=A, 2=B, 3=C, 4=D, 5=E, 6=F, 13=G, 14=H, 16=I, 26=J, 56=K, 63=L, 256=M. That gives us this potential cryptogram: JEDDHDLM ACM ACCBKEIDGM DD ACM AK GMDG CMEHDACJEDDHDLBKFDDGMEDHACCJEDDHDLMDG MEDHACCMEHDACMEDHACM ACM DD ACJDDLBK FFFGCMEHACM DD ACCM AK GBKFDDG However, there are some awfully long words in there, as well as a repeated word "DD", and a word starting "FFF", which I don't believe can be translated.

I think it's probable that there's additional steps needed, having to do with the actual values of the numbers, before doing any subsitutions, but at the moment I'm at a loss for what they may be.