2 added 4 characters in body edited Jun 26 '16 at 0:11 newzad 1,60777 silver badges1313 bronze badges OneBesides Will's comment another answer could be 0 Because if you Multiply first digit with $$x$$ and second digit with $$y$$ you get the following sequence: $$\left\{2x+6y, 2x, 4y, x+6y, x, 2y, x+4y \right\}$$The sequence of the differences between each term is $$\left\{6y, 2x-4y, -x-2y, 6y, x-2y, -x-2y,\right\}$$If second term $$(2x-4y)$$ and 5th $$(x-2y)$$ term are equal then certainly there is a pattern. If they are equal then $$x=2y$$ and the transformed sequence become $$\left\{10y, 4y, 4y, 8y, 2y, 2y, 6y \right\}$$ and the sequence of differences become $$\left\{6y, 0, -4y, 6y, 0, -4y,\right\}$$Hence the next term (answer) will be $$6y$$ less then the term before which makes it $$6y-6y=0$$ If you don't want to go in details just multiply the first digit with $$2$$ and the second digit with $$1$$, sum it to transform the sequence. You will see the some pattern. One answer could be 0 Because if you Multiply first digit with $$x$$ and second digit with $$y$$ you get the following sequence: $$\left\{2x+6y, 2x, 4y, x+6y, x, 2y, x+4y \right\}$$The sequence of the differences between each term is $$\left\{6y, 2x-4y, -x-2y, 6y, x-2y, -x-2y,\right\}$$If second term $$(2x-4y)$$ and 5th $$(x-2y)$$ term are equal then certainly there is a pattern. If they are equal then $$x=2y$$ and the transformed sequence become $$\left\{10y, 4y, 4y, 8y, 2y, 2y, 6y \right\}$$ and the sequence of differences become $$\left\{6y, 0, -4y, 6y, 0, -4y,\right\}$$Hence the next term (answer) will be $$6y$$ less then the term before which makes it $$6y-6y=0$$ If you don't want to go in details just multiply the first digit with $$2$$ and the second digit with $$1$$, sum it to transform the sequence. You will see the some pattern. Besides Will's comment another answer could be 0 Because if you Multiply first digit with $$x$$ and second digit with $$y$$ you get the following sequence: $$\left\{2x+6y, 2x, 4y, x+6y, x, 2y, x+4y \right\}$$The sequence of the differences between each term is $$\left\{6y, 2x-4y, -x-2y, 6y, x-2y, -x-2y,\right\}$$If second term $$(2x-4y)$$ and 5th $$(x-2y)$$ term are equal then certainly there is a pattern. If they are equal then $$x=2y$$ and the transformed sequence become $$\left\{10y, 4y, 4y, 8y, 2y, 2y, 6y \right\}$$ and the sequence of differences become $$\left\{6y, 0, -4y, 6y, 0, -4y,\right\}$$Hence the next term (answer) will be $$6y$$ less then the term before which makes it $$6y-6y=0$$ If you don't want to go in details just multiply the first digit with $$2$$ and the second digit with $$1$$, sum it to transform the sequence. You will see the some pattern. 1 answered Jun 25 '16 at 20:15 newzad 1,60777 silver badges1313 bronze badges One answer could be 0 Because if you Multiply first digit with $$x$$ and second digit with $$y$$ you get the following sequence: $$\left\{2x+6y, 2x, 4y, x+6y, x, 2y, x+4y \right\}$$The sequence of the differences between each term is $$\left\{6y, 2x-4y, -x-2y, 6y, x-2y, -x-2y,\right\}$$If second term $$(2x-4y)$$ and 5th $$(x-2y)$$ term are equal then certainly there is a pattern. If they are equal then $$x=2y$$ and the transformed sequence become $$\left\{10y, 4y, 4y, 8y, 2y, 2y, 6y \right\}$$ and the sequence of differences become $$\left\{6y, 0, -4y, 6y, 0, -4y,\right\}$$Hence the next term (answer) will be $$6y$$ less then the term before which makes it $$6y-6y=0$$ If you don't want to go in details just multiply the first digit with $$2$$ and the second digit with $$1$$, sum it to transform the sequence. You will see the some pattern.