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Peregrine Rook
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Given $N_1=26,~ N_2=20,~ N_3=4,~ N_4=16,~ N_5=10,~ N_6=2,$ and$N_1=26,~~ N_2=20,~~ N_3=4,~~ N_4=16,~~ N_5=10,~~ N_6=2,~$ and $N_7=14,$ and working backwards from

$N_8=8,$

which f'' found somewhere, I can reverse-engineer

\begin{align}N_1&=26~~\text{(seed value)}&N_4&=N_3+12&N_7&=N_6+12\\N_2&=N_1-6&N_5&=N_4-6&N_8&=N_7-6\\N_3&=N_2-2^4&N_6&=N_5-2^3&…\end{align}\begin{align}N_1&=26~~\text{(seed value)}&N_4&=N_3+12~~~&N_7&=N_6+12\\N_2&=N_1-6&N_5&=N_4-6&N_8&=N_7-6\\N_3&=N_2-2^4&N_6&=N_5-2^3&…\end{align}

… but that isn’t very satisfying.  You could probably construct equally plausible derivations for lots of other answers.

Given $N_1=26,~ N_2=20,~ N_3=4,~ N_4=16,~ N_5=10,~ N_6=2,$ and $N_7=14,$ and working backwards from

$N_8=8,$

which f'' found somewhere, I can reverse-engineer

\begin{align}N_1&=26~~\text{(seed value)}&N_4&=N_3+12&N_7&=N_6+12\\N_2&=N_1-6&N_5&=N_4-6&N_8&=N_7-6\\N_3&=N_2-2^4&N_6&=N_5-2^3&…\end{align}

… but that isn’t very satisfying.  You could probably construct equally plausible derivations for lots of other answers.

Given $N_1=26,~~ N_2=20,~~ N_3=4,~~ N_4=16,~~ N_5=10,~~ N_6=2,~$ and $N_7=14,$ and working backwards from

$N_8=8,$

which f'' found somewhere, I can reverse-engineer

\begin{align}N_1&=26~~\text{(seed value)}&N_4&=N_3+12~~~&N_7&=N_6+12\\N_2&=N_1-6&N_5&=N_4-6&N_8&=N_7-6\\N_3&=N_2-2^4&N_6&=N_5-2^3&…\end{align}

… but that isn’t very satisfying.  You could probably construct equally plausible derivations for lots of other answers.

Source Link
Peregrine Rook
  • 4.9k
  • 2
  • 26
  • 40

Given $N_1=26,~ N_2=20,~ N_3=4,~ N_4=16,~ N_5=10,~ N_6=2,$ and $N_7=14,$ and working backwards from

$N_8=8,$

which f'' found somewhere, I can reverse-engineer

\begin{align}N_1&=26~~\text{(seed value)}&N_4&=N_3+12&N_7&=N_6+12\\N_2&=N_1-6&N_5&=N_4-6&N_8&=N_7-6\\N_3&=N_2-2^4&N_6&=N_5-2^3&…\end{align}

… but that isn’t very satisfying.  You could probably construct equally plausible derivations for lots of other answers.