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Is itEDIT: Thanks to MariusSiuram the upper bound is
$2^{100}$
Because
The sum of any two of $2^0, 2^1, 2^2, 2^3 \dots 2^{100}$ are different and lower numbers double up sumsdifferet.
Is it
The sum of any two of $2^0, 2^1, 2^2, 2^3 \dots 2^{100}$ are different and lower numbers double up sums.
EDIT: Thanks to MariusSiuram the upper bound is
The sum of any two of $2^0, 2^1, 2^2, 2^3 \dots 2^{100}$ are differet.