Timeline for The asymmetric coin game
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Apr 6, 2016 at 22:22 | history | suggested | Peregrine Rook | CC BY-SA 3.0 |
Fixed typo (Bob ↔ n → 2n) and put variables into MathJax.
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| Apr 6, 2016 at 22:13 | review | Suggested edits | |||
| S Apr 6, 2016 at 22:22 | |||||
| Apr 6, 2016 at 19:33 | comment | added | ffao | I didn't know this was a well-known identity, I ended up proving it again when making this puzzle (i.e. what f'' did) | |
| Apr 6, 2016 at 19:31 | comment | added | Tony Ruth | @Lacklub I think its right now. Also added some parentheses. | |
| Apr 6, 2016 at 19:31 | history | edited | Tony Ruth | CC BY-SA 3.0 |
added 16 characters in body
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| Apr 6, 2016 at 19:30 | comment | added | Lacklub | You dropped the $\frac{1}{2^{3n}}$ | |
| Apr 6, 2016 at 19:28 | history | edited | Tony Ruth | CC BY-SA 3.0 |
deleted 10 characters in body
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| Apr 6, 2016 at 19:25 | comment | added | Anon | Note that by Vandermonde's identity, $\sum_{i=0}^n\binom{n}{i}\binom{2n}{i} = \sum_{i=0}^n\binom{n}{n-i}\binom{2n}{i} = \binom{3n}{n}$. | |
| Apr 6, 2016 at 19:23 | history | edited | Tony Ruth | CC BY-SA 3.0 |
added 2 characters in body
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| Apr 6, 2016 at 19:18 | history | answered | Tony Ruth | CC BY-SA 3.0 |