Timeline for Three voting prisoners
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Jun 17, 2020 at 8:22 | history | edited | CommunityBot |
Commonmark migration
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| Oct 1, 2015 at 18:43 | history | edited | Puzzle Prime | CC BY-SA 3.0 |
deleted 67 characters in body
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| Oct 1, 2015 at 18:07 | history | edited | Puzzle Prime | CC BY-SA 3.0 |
added 14 characters in body
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| Oct 1, 2015 at 17:58 | history | edited | Puzzle Prime | CC BY-SA 3.0 |
deleted 91 characters in body
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| Oct 1, 2015 at 17:57 | comment | added | Puzzle Prime | @Spacemonkey, you are right, it may happen on the second day. Thanks for the remark! | |
| Oct 1, 2015 at 17:44 | history | edited | Puzzle Prime | CC BY-SA 3.0 |
added 20 characters in body
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| Oct 1, 2015 at 17:40 | comment | added | Spacemonkey | Good solution, I was in the process of reasoning this and you found it/complete it before I could, also kudos for the 'no math' answer. Key is indeed even/odd amount of days. Will +1 when I have more votes. However this doesn't necessarily free them on the first possible night in a scenario where every night the steak dinner alternates from one to another (ratio 1-1-1) as the 'consecutive' part will mean the one with the steak will vote 1, and the other 2 will vote 2 (because they've only eaten 1 consecutive steak dinner) | |
| Oct 1, 2015 at 17:21 | history | answered | Puzzle Prime | CC BY-SA 3.0 |