Timeline for Prove that all 101 balls have the same weight
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Oct 29 at 10:58 | comment | added | Cyriac Antony | (Follow-up to the comment) For n=3, "1,3,5,7,9,11,13" is not a solution since we can not partition into sets of 3 of equal weights after removing 1. Also, the question and the proof argument look correct to me. | |
| Oct 29 at 10:52 | comment | added | Jaap Scherphuis | "Thus it can have at most one solution." This is not true. We already know there are infinitely many solutions, cause all the weights could be 1 gram, or all could be 100 grams, etc. The 2n+1 equations are not independent. For example with three balls you have the equations a=b, b=c, a=c which are obviously not independent. The question is whether there could be further dependencies between the equations in any one of the possible systems of equations you could have for 2n+1 balls. | |
| Oct 29 at 10:47 | comment | added | Cyriac Antony | For n=3, is "1,3,5,7,9,11,13" a solution? Doesn't this mean the question is (and the proof argument given are) wrong? | |
| Oct 29 at 10:08 | review | Late answers | |||
| Oct 29 at 13:03 | |||||
| S Oct 29 at 9:49 | review | First answers | |||
| Oct 29 at 11:32 | |||||
| S Oct 29 at 9:49 | history | answered | Jacob Antony | CC BY-SA 4.0 |