Timeline for Can you arrange 25 whole numbers (not necessarily all different) so that the sum of any three successive terms is even but the sum of all 25 is odd?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jul 3 at 7:31 | history | edited | Richard Kirk | CC BY-SA 4.0 |
Better syntax. Argument unchanged.
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| Jul 2 at 17:31 | comment | added | Will.Octagon.Gibson | @RichardKirk Welcome to PSE (Puzzling Stack Exchange)! | |
| Jul 2 at 16:45 | comment | added | Daniel Mathias | The reverse of any valid sequence is also a valid sequence. The two binary solutions are equivalent. | |
| Jul 2 at 16:27 | comment | added | Richard Kirk | @DanielMathias I have changed my working to give solutions for a total odd sum. Has this question been edited? The one that I answered (rightly or wrongly) had a single solution, so it was a better problem. PS: it has not been edited. | |
| S Jul 2 at 16:25 | review | First answers | |||
| Jul 2 at 17:13 | |||||
| S Jul 2 at 16:25 | history | edited | Richard Kirk | CC BY-SA 4.0 |
Changed as per comment
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| Jul 2 at 16:11 | comment | added | Daniel Mathias | Your solution has a sum of 16, which does not meet the required condition of an overall odd sum. | |
| S Jul 2 at 12:03 | review | First answers | |||
| Jul 2 at 14:18 | |||||
| S Jul 2 at 12:03 | history | answered | Richard Kirk | CC BY-SA 4.0 |