Timeline for Amelia Earhart Challenge
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 20, 2015 at 12:37 | comment | added | A.D. | I see your point. Yes it's one fourth to each of the other planes. | |
| Apr 19, 2015 at 23:40 | comment | added | geometrian | Ambiguity in language. "p2 gives a fourth of its tank capacity to the two other planes" means most directly "p2 transfers a fourth of its tank capacity to the two other planes jointly", not "p2 transfers half of its tank capacity to the two other planes to split". In exactly the same way as kaine's answer, your answer is correct under this clarification. | |
| Apr 19, 2015 at 23:36 | comment | added | A.D. | Still don't understand what you mean. | |
| Apr 19, 2015 at 23:32 | comment | added | geometrian | See discussion on kaine's answer. | |
| Apr 19, 2015 at 23:30 | comment | added | A.D. | I don't understand what you're saying. At step 2, p2 give one fourth to p1 and one fourth to p3. As p1 and p3 have burn each one fourth of their tank, now it is full again. | |
| Apr 19, 2015 at 22:57 | comment | added | geometrian | Similar problem. In step 2, p1 and p3 do not have a full tank, since they have together burned 1/4 + 1/4 = 1/2 a tank (they are burning at the same time). | |
| Apr 19, 2015 at 21:52 | history | answered | A.D. | CC BY-SA 3.0 |