Skip to main content
3 events
when toggle format what by license comment
Dec 5, 2023 at 15:20 comment added Bass The first step ("If the upper right hand square [1,3, or 4] is a 3") feels a lot like "try something and see if it turns out impossible". This is called bifurcation (which in its extreme form is basically just guessing), and even if you were a person that doesn't mind a method being somewhat distasteful as long as it produces results, the specific thought chain is unnecessarily long in both directions: You could just say: "if r3c6 is a 1, then both the bottom left squares are twos", and be done with it.
Dec 5, 2023 at 11:07 comment added justhalf I'm not following. If R1C6 is 3, then R3C6 is 1, R4C5 is 3, R6C5 is 1. Then R6C2 is 2 and R6C1 is 3. R5C2 and R5C3 are then 1,4 pair. No contradiction there yet, it seems?
Dec 5, 2023 at 10:17 history answered user121330 CC BY-SA 4.0