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Jiminion
Jiminion
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I think the answer is :

(6, 12) or (6, 36)

If x is NOT one of 6, 12 or 36, then the first mathematician would know the other one's number, so the numbers are definitely 6, 12 or 36.

If x was 6, then y could be either 12 or 36 (as 36 to the 6th power is also an answer). So first mathematician can't be sure. Therefore his number is 6.

The second mathematician's number is either 12 or 36, so he knows x must be 6. Then the first mathematician knows that the numbers are either (6, 12) or (6, 36).

I think the answer is :

(6, 12) or (6, 36)

If x is one of 6, 12 or 36, then the first mathematician would know the other one's number, so the numbers are definitely 6, 12 or 36.

If x was 6, then y could be either 12 or 36 (as 36 to the 6th power is also an answer). So first mathematician can't be sure. Therefore his number is 6.

The second mathematician's number is either 12 or 36, so he knows x must be 6. Then the first mathematician knows that the numbers are either (6, 12) or (6, 36).

I think the answer is :

(6, 12) or (6, 36)

If x is NOT one of 6, 12 or 36, then the first mathematician would know the other one's number, so the numbers are definitely 6, 12 or 36.

If x was 6, then y could be either 12 or 36 (as 36 to the 6th power is also an answer). So first mathematician can't be sure. Therefore his number is 6.

The second mathematician's number is either 12 or 36, so he knows x must be 6. Then the first mathematician knows that the numbers are either (6, 12) or (6, 36).

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edit approved Apr 17, 2015 at 16:22
GentlePurpleRain
edit approved Apr 17, 2015 at 16:22
GentlePurpleRain
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I think the answer is :

6,12(6, 12) or 6, 36(6, 36)

If xx is not eitherone of 6 or, 12 or 36, then the first mathematician would know the other one's number, so the numbers are definitely 6  , 12 or 36. If x

If x was 6, then yy could be either 12 or 36 (as 36 to the 66th power is also an answer). So first mathematician can't be sure. His Therefore his number is 6. 2nd mathematician

The second mathematician's number is either 12 or 36. He, so he knows xx must be 6. 1st Then the first mathematician knows then that numberthe numbers are either 6, 12(6, 12) or 6, 36(6, 36).

I think the answer is :

6,12 or 6, 36 If x is not either 6 or 12 or 36, then the first mathematician would know the other one's number, so the numbers are definitely 6  , 12 or 36. If x was 6, then y could be either 12 or 36 (as 36 to the 6 is also an answer). So first mathematician can't be sure. His number is 6. 2nd mathematician is either 12 or 36. He knows x must be 6. 1st mathematician knows then that number are either 6, 12 or 6, 36.

I think the answer is :

(6, 12) or (6, 36)

If x is one of 6, 12 or 36, then the first mathematician would know the other one's number, so the numbers are definitely 6, 12 or 36.

If x was 6, then y could be either 12 or 36 (as 36 to the 6th power is also an answer). So first mathematician can't be sure. Therefore his number is 6.

The second mathematician's number is either 12 or 36, so he knows x must be 6. Then the first mathematician knows that the numbers are either (6, 12) or (6, 36).

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Jiminion
Jiminion
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I think the answer is :

6,12 or 6, 36 If x is not either 6 or 12 or 36, then the first mathematician would know the other one's number, so the numbers are definitely 6 , 12 or 36. If x was 6, then y could be either 12 or 36 (as 36 to the 6 is also an answer). So first mathematician can't be sure. His number is 6. 2nd mathematician is either 12 or 36. He knows x must be 6. 1st mathematician knows then that number are either 6, 12 or 6, 36.