New solution found by hand using all the operations and all the digits in same sequence -

-(-1+2-3x(-4+5)x6)x(7x(8+9))

Here's a solution using all the operations except subtraction and the digits in the same order.

(((1/2)x34)+56)x(7x(8+9))

Some proofs

Solve path

I looked for factors of 2023 and found 17 and 119. Looked for factors of 119 and found 7 amd 17. Tada, I can use 7,8,9 to get 119. Now, 17 is a prime number. No factors. So, a bit of trial and errors and we can easily use digits 1,2,3,4,5,6 to get 17. Idea was to use bigger digits 5,6 with additions/substractions and smaller ones for other operations.

Here's a solution using all the operations and the digits in the same order.

$((-(-1)/2)*3*4)+5+6)*(7*(8+9))$

Some proofs

Solve path

I looked for factors of 2023 and found 17 and 119. Looked for factors of 119 and found 7 amd 17. Tada, I can use 7,8,9 to get 119. Now, 17 is a prime number. No factors. So, a bit of trial and errors and we can easily use digits 1,2,3,4,5,6 to get 17. Idea was to use bigger digits 5,6 with additions/substractions and smaller ones for other operations.

Here's a solution found by hand using all the operations and the digits in the same order.

(((1/2)x3x4)+5+6)x(7x(8+9))

Some proofs

Solve path

I looked for factors of 2023 and found 17 and 119. Looked for factors of 119 and found 7 amd 17. Tada, I can use 7,8,9 to get 119. Now, 17 is a prime number. No factors. So, a bit of trial and errors and we can easily use digits 1,2,3,4,5,6 to get 17. Idea was to use bigger digits 5,6 with additions/substractions and smaller ones for other operations.

New solution found by hand using all the operations and all the digits in same sequence -

-(-1+2-3x(-4+5)x6)x(7x(8+9))

Here's a solution using all the operations except subtraction and the digits in the same order.

(((1/2)x34)+56)x(7x(8+9))

Some proofs

Solve path

I looked for factors of 2023 and found 17 and 119. Looked for factors of 119 and found 7 amd 17. Tada, I can use 7,8,9 to get 119. Now, 17 is a prime number. No factors. So, a bit of trial and errors and we can easily use digits 1,2,3,4,5,6 to get 17. Idea was to use bigger digits 5,6 with additions/substractions and smaller ones for other operations.