Timeline for Ripple Effect ... with Inequality Sign
Current License: CC BY-SA 4.0
12 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Oct 22, 2021 at 15:53 | vote | accept | Nusi | ||
Oct 22, 2021 at 15:53 | comment | added | Nusi | It should be good right now. Great explanation! :D | |
Oct 22, 2021 at 11:30 | comment | added | Stiv | Thanks for flagging that up @Retudin - yes, that was an error in my explanation; I did say it was a difficult puzzle! :) I've replaced the problematic section with a better proof by contradiction that should definitely work. | |
Oct 22, 2021 at 11:29 | history | edited | Stiv | CC BY-SA 4.0 |
Contradictory contradiction contraindicated (i.e. all fixed now, I hope...)
|
Oct 22, 2021 at 10:07 | comment | added | Retudin | Step 2: "those that will be present in the two 2x2 squares in rows 3-4". Maybe I am missing something, but this seems incorrect reasoning: The squares can use column 1+6 of the same row. | |
Oct 22, 2021 at 8:38 | history | edited | Stiv | CC BY-SA 4.0 |
Minor typo corrected and rewording
|
Oct 22, 2021 at 8:03 | comment | added | Stiv | @Nusi I think that should now all be fixed! (Unless your eagle eye spots anything else I have foolishly done!) Thanks for pointing that out :) | |
Oct 22, 2021 at 8:01 | history | edited | Stiv | CC BY-SA 4.0 |
Fixed logic
|
Oct 22, 2021 at 7:25 | comment | added | Nusi | I think I'm missing something. In the third picture of step 2, why r3c1 cannot be 4? Can you please elaborate it? Thanks! :D | |
Oct 21, 2021 at 23:04 | comment | added | Avi | Very tricky puzzle indeed - I wasn't even able to make an initial breakthrough | |
Oct 21, 2021 at 22:19 | comment | added | Stevo | You quite literally beat me to it; was just starting writing up my answer. | |
Oct 21, 2021 at 22:13 | history | answered | Stiv | CC BY-SA 4.0 |