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Oct 7, 2021 at 13:51 comment added Nautilus Better than mine, so here's an upvote.
Sep 10, 2021 at 21:03 comment added JS1 OK I see it now. Your pictures were so small I couldn't read them properly. The bottom pentagon is labeled 1.75 + sqrt(3) and I thought it was labeled 1.25 + sqrt(3). I see now that the bottom pentagon is bounded by 1.75 at the longest point, which makes the left edge of "D" be 0.875 which looks about right according to the diagram. One thing I didn't get before is that if the angel hides in the bottom area, you don't have to bisect A/B. Therefore, the C/D area should be bigger than the A/B area because you "save" 0.5 by not needing to bisect A/B.
Sep 10, 2021 at 20:48 comment added Retudin The first half is a reasoning of how to get to an optimal solution. I did indeed not explain where the split 3b between C and D is. 3b is just a rough estimate, and it will not be a single strait line according to my reasoning. Only starting at picture 3 I used the bounding rectangle approach to get to a 'simple' upper bound solution below 7. The C,D equivalents in picture 4 uses a bounding box of 1.75/2 and sqrt(3)/2 (and there 3b will be the orthogonal line of length sqrt(3)/2)
Sep 10, 2021 at 20:15 comment added JS1 Where exactly do you cut to divide regions "C" and "D"? From your diagram, region "D" looks like the left edge has a length greater than 1.25/2, but your final result seems to depend on both C and D having bounding boxes of sides 1.25/2 and sqrt(3)/2.
Sep 10, 2021 at 16:22 comment added Retudin Not sure if this helps much, but at least they are easier to see now without the need to click on them for enlargement..
Sep 10, 2021 at 16:20 history edited Retudin CC BY-SA 4.0
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Sep 10, 2021 at 15:53 comment added Eric That's really good! May I suggest that you post the four pictures separately in finer resolution to be seen more clearly?
Sep 10, 2021 at 14:35 history answered Retudin CC BY-SA 4.0