Skip to main content
24 events
when toggle format what by license comment
Jun 30, 2021 at 17:29 comment added ROX My answer shows that in lucky cases it can be done in 2 questions. There's another solution where you could solve it by asking 2 distinct questions, asking the same question twice (so that's still 3 questions, just that 2 are the same).
S Jun 30, 2021 at 9:35 history suggested Hemant Agarwal CC BY-SA 4.0
it wasn't clear what "each question can be targetted to multiple people" meant . I removed the ambiguity.
Jun 30, 2021 at 9:34 review Suggested edits
S Jun 30, 2021 at 9:35
Jun 30, 2021 at 9:33 history edited Andrew CC BY-SA 4.0
added 84 characters in body
Jun 30, 2021 at 8:40 vote accept Andrew
Jun 30, 2021 at 8:40 comment added Andrew If there is such a proof, I'd like to know about it.
Jun 30, 2021 at 6:38 comment added Saikat I would like to complement you on your creativity. The two additional people who always say 'yes' or 'no' is a splendid twist. Is there a proof for the lower bound of 3 ?
Jun 28, 2021 at 21:16 answer added ROX timeline score: 10
Jun 28, 2021 at 13:59 comment added Arnaud Mortier The other main difference between this and the Hardest Puzzle is that you can here ask one question to multiple people. This makes it a LOT easier.
Jun 28, 2021 at 11:43 comment added jymbob @Deusovi due to the ambiguity, that's not a yes/no question. More fully: truth-teller will answer "I don't know", yesser will answer "yes", noer will answer "no", liar will answer something that cannot be true (I'm going to go with "applesauce") and the coin flipper will say either "yes" or "no"
Jun 28, 2021 at 9:27 history edited Andrew CC BY-SA 4.0
added 56 characters in body
Jun 28, 2021 at 3:11 history became hot network question
Jun 28, 2021 at 2:27 answer added Deusovi timeline score: 43
Jun 28, 2021 at 0:49 comment added Deusovi What happens if you ask a question that could go either way (e.g. you ask the truthteller "What would the coin-flipper say if I asked him whether 2+2=4?")?
Jun 27, 2021 at 21:52 history edited Andrew CC BY-SA 4.0
added 33 characters in body
Jun 27, 2021 at 19:09 history edited Andrew CC BY-SA 4.0
added 33 characters in body
Jun 27, 2021 at 19:08 comment added Gareth McCaughan I think the puzzle statement should say whether each person knows which ones the others are.
Jun 27, 2021 at 17:20 comment added Sagar Chand I can find 4. I guess others would have figured it out as well. Its just that there is possibility that our flip guy flips for 3 questions and gets same outcome(say HEADS). Then there is no difference between the "flip" guy and the "yes" guy
Jun 27, 2021 at 15:41 comment added Andrew I have clarified my metric for a single question. One question = one single question that you make, even if multiple guards are intended to answer it. If it still looks intractable, what's the deadline by which I have to post a solution? And do I edit it into the question or post it as an answer?
Jun 27, 2021 at 15:40 history edited Andrew CC BY-SA 4.0
added 52 characters in body
Jun 27, 2021 at 13:54 comment added justhalf @TakingNotes, hm, yea, on first look it seems impossible. There are 5!=120 possible orders, but 3 yes/no questions cover only 8 possibilities. Would like to see the solution later.
Jun 27, 2021 at 12:50 history edited Andrew CC BY-SA 4.0
added 22 characters in body
Jun 27, 2021 at 12:45 comment added TakingNotes This seems impossible because there are three people who are completely ambiguous in the answer, and you can only ask 3 questions. If I'm missing something in the question I'd love somebody to point it out for me...
Jun 27, 2021 at 11:42 history asked Andrew CC BY-SA 4.0