Timeline for Can you create a Minesweeper puzzle with 'information crossover'?
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Mar 24, 2015 at 15:49 | comment | added | KSmarts | The status of ABCD is unknown at the start of the game (by how minesweeper works). The possibility of the "all mines" solution means that none of the squares are "safe," regardless of whether they actually have mines or not. | |
Mar 24, 2015 at 15:42 | comment | added | Lopsy | The intention of rule 3 is that there should be a solution where (for example) A and C are both mines and B and D are both safe. That is, all 4 mine-settings of A, B, C, D satisfying A=C and B=D extend to a solution. I see now that I phrased this rule badly, sorry to the solvers so far. | |
Mar 24, 2015 at 15:34 | comment | added | Ian MacDonald | @KSmarts: See the second spoiler block. | |
Mar 24, 2015 at 15:33 | comment | added | KSmarts | How does this not have the "anything is a solution" problem that @JBSregath's second answer does? | |
Mar 24, 2015 at 15:31 | comment | added | Ian MacDonald | It follows the rules laid out in the challenge and it follows the rules of Minesweeper as they are modified to include holes. It's really just a question of what makes a "smaller grid". 4 non-hole squares is smaller than 8 non-hole squares, but they take up more space if you include the holes in the calculation. | |
Mar 24, 2015 at 15:27 | comment | added | JBSregath | This could be a solution indeed, but there might be a possibility this is not allowed because none of the sides are touching, thus not a minesweeper puzzle. I'll leave it up to Lopsy | |
Mar 24, 2015 at 15:21 | history | answered | Ian MacDonald | CC BY-SA 3.0 |