Here's an example that beats the OP's:
|11 41 7| 59 |47 3 17| 67 |13 83 5| 101 ------------ 23 71 127 29 19
I got this by putting the smallest possible number (3) in the most central position (which is involved in 3four of the 8eight sums) and then the next smallest numbers (5, 7, 11, 13) in the positions involved in 2three of the 8eight sums, so that $S_1+\dots+S_8$ is minimised. I believe this may be the best possible.