Timeline for Does a systematic way to solve a magic square made up of domino pieces exist?
Current License: CC BY-SA 4.0
6 events
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| Oct 27, 2020 at 9:03 | comment | added | Florian F | What I did is I first created a magic square with values 0 to 3. Then I split it into dominoes. My first version used only vertical tiles, resulting in only 2 tiles ([0,1] and [2,3]) being used 4 times each. So I replaced some vertical pairs by horizontals. Then it required a [1,3] tile which is not available, so I switched the 0's and 1's. So yes, trial and error. | |
| Oct 27, 2020 at 2:18 | comment | added | Chris Steinbeck Bell | Again Can you include which sorts of steps you used to get that combination?. Was it just trial and error?. Or does it exist some sort of thing which I should attempt to began to look for first?. | |
| Oct 27, 2020 at 2:17 | comment | added | Chris Steinbeck Bell | Interesting approach. As I mentioned there isn't a statement which indicated to use all the pieces. It seems that in order to solve this you may use one some of them which would yield a magic square. However what steps have you used to get that magic square?. Was it just trial and error?. What I attempted to do at first was to sum all dots. By doing this I obtained $20$ and this can be split in two halves of 10 and $10$ I assumed that the sum of the diagonal to be $5$. But it isn't the case it was $6$. | |
| Oct 26, 2020 at 17:43 | history | edited | Florian F | CC BY-SA 4.0 |
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| Oct 26, 2020 at 17:21 | history | edited | Florian F | CC BY-SA 4.0 |
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| Oct 26, 2020 at 17:16 | history | answered | Florian F | CC BY-SA 4.0 |